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To be 1-A, one must physically exist outside or independent of an infinite tiering of High 1-B, and to be High 1-A, one must physically exist outside or independent of an infinite tiering of 1-As the same way 1-A transcends High 1-B?
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Transcending H1B structure and exist outside H1B structureTo be 1-A, one must physically exist outside or independent of an infinite tiering of High 1-B, and to be High 1-A, one must physically exist outside or independent of an infinite tiering of 1-As the same way 1-A transcends High 1-B?
Infinite Higher dimension^ infinite higher dimension=L1aTrascending High 1-B is Low 1-A
Trascending Low 1-A is 1-A.
Trascending all possible extensions of 1-A is High 1-A
you are saying "ω^ω" is 1-A? it's still High 1-B, it's still ℵ0.Infinite Higher dimension^ infinite higher dimension=L1a
Infinite^Infinite^Infinite up to infinite is still ℵ0, precisally ω+ωIt's only High 1-B because of infinite^infinite higher dimensions
Infinite^infinite^infinite up to until infinitely amount of higher dimensions is Low 1-A
Transcending any expansion of a infinite layered hierarchy = 1-ATo be 1-A, one must physically exist outside or independent of an infinite tiering of High 1-B, and to be High 1-A, one must physically exist outside or independent of an infinite tiering of 1-As the same way 1-A transcends High 1-B?
Ah, my badInfinite^Infinite^Infinite up to infinite is still ℵ0, precisally ω+ω