Smallest number of dimensions for a multiverse

[Nakaos]

Sorry if the question sounds dumb, but I was wondering how many dimensions are required to create a multiverse, or more specifically a structure who contains more than one 4-dimensional space-time continuum?

For me, it's seems obvious we need at least a 5th dimension, either spatial or temporal, but I'm not actually 100% sure of this. Is it possible to create 2 4-dimensional space-time continuum with only 4 dimentions? And what is the case if said universes are actually (finite) pocket universes (still 4D of course)?

 

[Yumi-tan]

According to M-Theory. Multiverse consist of 5 dimension. Length, width, heighth, time, and fifth spatial dimension. But there other theory that say other stuff.

String Theory propose 11 dimension multiverse. Bosonic String Theory- 26 dimension multiverse.

There is even Hilbert Space. Which infinite dimension. :O

However, multiverse merely multiple universes or branes. Universe being 4-D brane. So 5 dimension requires to have infinite 4-D brane and size don't matter.

Yes, there can be two 4-D universe in 4-D space, just like there are bazillions of 3-D objects in 3-D universe.

 

[Antvasima]

Yumi-tan is correct. Or at least she summarised my own knowledge regarding the issue.

 

[Nakaos]

Yes, there can be two 4-D universe in 4-D space, just like there are bazillions of 3-D objects in 3-D universe.
Thanks Yumi, now I see what bothered me.

If I divide a infinite volume by an infinite value, I may obtain an infinite number of infinite volume. So it would be okay to think we can create a multiverse with only 4 dimensions. However, if this statement is true, that would mean that an infinite universe is also a multiverse of infinite universes.

That's why I think we can't create two 4-D universes within a 4-D space and need a 5th dimension anyway...Am I missing something?

 

[Antvasima]

Well, as universes can be endless in size, two universal clusters within the same 4-D space are usually considered as part of the same time-space continuum, i.e. it counts as Low 2-C.

 

[Nakaos]

That seems logical to me, thanks for the answer.

 

[Antvasima]

No problem.