Question about 3-A and L2-C.

[UchihaLik]

3-A/H3-A is destruction of the space of the universe, L2-C is destruction of the entire space-time continuum of the universe, this is already 4D due to the destruction of the time axis....How does this even work? Time axis is one for the entire verse, simply destroying a universe in a multiverse will not destroy the time axis. But, if the character clearly said that he destroyed the "Space-Time Continuum of the Universe in the Multiverse"... Is it L2-C or 3-A? In theory, the time axis is still untouched, because it is located on a much larger scale - on the scale of the whole verse, not just this one universe. If this is L2-C then it turns out that this universe has its own time axis? Then in the multiverse the number of time axes is equal to the number of universes + 1. Please explain.

 

[Lloydblitzed]

3-A/H3-A is destruction of the space of the universe, L2-C is destruction of the entire space-time continuum of the universe, this is already 4D due to the destruction of the time axis....How does this even work?

You destroy every physical matter of the Universe --> 3-A
You destroy a Space-Time continuum --> Low 2-C

But, if the character clearly said that he destroyed the "Space-Time Continuum of the Universe in the Multiverse"... Is it L2-C or 3-A?

That's Low 2-C. The character is destroying the Space Time continuum of the Universe which is located inside the Multiverse. In short, he's vaporizing one of the Space-Time continuums who are part of the Multiverse, they do not necesserally affect the entire cosmo

In theory, the time axis is still untouched, because it is located on a much larger scale - on the scale of the whole verse, not just this one universe. If this is L2-C then it turns out that this universe has its own time axis?

Im not sure if the Universe having its own time axis matters, unless you wanna prove the Universe is its own Space-Time seperated from other space-times or something