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Question about 3-A and L2-C.

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3-A/H3-A is destruction of the space of the universe, L2-C is destruction of the entire space-time continuum of the universe, this is already 4D due to the destruction of the time axis....How does this even work? Time axis is one for the entire verse, simply destroying a universe in a multiverse will not destroy the time axis. But, if the character clearly said that he destroyed the "Space-Time Continuum of the Universe in the Multiverse"... Is it L2-C or 3-A? In theory, the time axis is still untouched, because it is located on a much larger scale - on the scale of the whole verse, not just this one universe. If this is L2-C then it turns out that this universe has its own time axis? Then in the multiverse the number of time axes is equal to the number of universes + 1. Please explain.
 
3-A/H3-A is destruction of the space of the universe, L2-C is destruction of the entire space-time continuum of the universe, this is already 4D due to the destruction of the time axis....How does this even work?
You destroy every physical matter of the Universe --> 3-A
You destroy a Space-Time continuum --> Low 2-C
But, if the character clearly said that he destroyed the "Space-Time Continuum of the Universe in the Multiverse"... Is it L2-C or 3-A?
That's Low 2-C. The character is destroying the Space Time continuum of the Universe which is located inside the Multiverse. In short, he's vaporizing one of the Space-Time continuums who are part of the Multiverse, they do not necesserally affect the entire cosmo
In theory, the time axis is still untouched, because it is located on a much larger scale - on the scale of the whole verse, not just this one universe. If this is L2-C then it turns out that this universe has its own time axis?
Im not sure if the Universe having its own time axis matters, unless you wanna prove the Universe is its own Space-Time seperated from other space-times or something
 
3-A/H3-A evrenin uzayının yıkımı altındadır, L2-C evrenin tüm uzay-zaman sürekliliğinin yıkımı altındadır, bu zaten zaman ekseninin yıkımı nedeniyle 4D'dir... Bu nasıl çalışır?
3-A https://vsbattles.fandom.com/wiki/Category:Tier_3-A What is meant here is to destroy all materiality of the (3-D) area that covers the X Y Z spatial dimensions of the universe.
In other words, destroying the 3-dimensional spatial field similar to the observable universe is scaled to the 3-A level.
H3-A https://vsbattles.fandom.com/wiki/Kategori:Yüksek_Seviye_3-A
What is meant here is to destroy all infinite materiality and energy in the infinite field-space on the X Y Z spatial 3-dimensional scale.
that is, to destroy all the infinite materiality of the 3-dimensional spatial field, except for temporal dimensions.
For the L2-C stage, it is necessary to destroy the infinite space-time continuum, which contains temporal dimensions in addition to spatial dimensions.




Tüm kıta için aynı anda, çoklu evrendeki bir evreni yok etmek isteyen bir evreni yok etmez. "Çoklu Evren'in Evren-Zaman'ı" yok diyorsanız... L2-C mi yoksa 3-A mı?
Destroying the space-time continuum of a universe within the multiverse is at the L2C level. The space-time continuum of the destroyed universe is different from the space-time continuum of the multiverse.


Teoride, zaman hala somut bir şekilde ortaya çıkmamıştır, çünkü çok daha büyük bir ölçekte yer almaktadır - sadece bu evrenin değil, tüm kıtanın ölçeğinde. Peki L2-C ise, bu evrenin kendine özgü bir ekseni olduğu ortaya çıkıyor mu? O zaman çoklu evrende birden fazla evren sayısı + 1'e ulaştı. Lütfen açıklayın.
The fact that the multiverse has its own space-time continuum is irrelevant to the destruction of the space-time continuum of the universe within the multiverse.
When the space-time continuum of the universe within the multiverse is destroyed, the space-time continuum of the multiverse will still exist. However, this performance still scales to the L2-C rank.
 
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