How many MegaParsecs are in the Observable Unverse?

[CNBA3]

I know that based on current information that the radius of the Observable Universe is roughly 14288 Megaparsecs.

but I was wondering, uniformly, with the entire sphere volume, how any marks can you fit with a distance between them is a megaparsec?

 

[TWILIGHT-OP]

The observable universe is thus a sphere with a diameter of about 28.5 gigaparsecs[32] (93 billion light-years or 8.8×1026 m).

 

[Flashlight237]

Ermm... 1 gigaparsec is 1000 megaparsecs. Try doing the math from there.

 

[CNBA3]

The observable universe is thus a sphere with a diameter of about 28.5 gigaparsecs[32] (93 billion light-years or 8.8×1026 m).

Ermm... 1 gigaparsec is 1000 megaparsecs. Try doing the math from there.

Thanks, just one question tho, would finding the volume give the number of megaparsecs within the universe? Like points between each megaparsecs it can be filled?

otherwise the volume of the universe would be 1.22e+13 megaparsecs^3

 

[CNBA3]

I did a quick calculation for at least Gigaparsecs through pixel scaling of the chart here.





27 px = 1 gigaparsec = 1000 megaparsecs = 3.262e+9 LY

.027 px = 1 megaparsec = 3.262e+6 LY

8 px = 1000000000 LY = 306.6 megaparsecs

4 px = 500000000 LY = 153.3 megaparsecs

1 gigaparsecs = 1000 megaparsecs

Radius = 347 px = 13 gigaparsecs

----

Circumference OL = 2374.92 px = 87.96 gigaparsecs
# of Gigaparsecs = 88

Circumference O#1 =2205.36 px = 81.68 gigaparsecs
# of Gigaparsecs = 82

Circumference O#2 = 2035.8 px = 75.4 gigaparsecs
# of Gigaparsecs = 75

Circumference O#3 = 1866.24 px = 69.12 gigaparsecs
# of Gigaparsecs = 69

Circumference O#4 = 1696.41 px = 62.83 gigaparsecs
# of Gigaparsecs = 63

Circumference O#5 = 1526.85 px = 56.55 gigaparsecs
# of Gigaparsecs = 57

Circumference O#6 = 1357.29 px = 50.27 gigaparsecs
# of Gigaparsecs = 50

Circumference O#7 = 1187.46 px = 43.98 gigaparsecs
# of Gigaparsecs = 44

Circumference O#8 = 1017.9 px = 37.7 gigaparsecs
# of Gigaparsecs = 38

Circumference O#9 = 848.34 px = 31.42 gigaparsecs
# of Gigaparsecs = 31

Circumference O#10 = 678.51 px = 25.13 gigaparsecs
# of Gigaparsecs = 25

Circumference O#11 = 508.95 px = 18.85 gigaparsecs
# of Gigaparsecs = 19

Circumference O#12 = 339.39 px = 12.57 gigaparsecs
# of Gigaparsecs = 13

Circumference O#13 = 169.56 px = 6.28 gigaparsecs
# of Gigaparsecs = 6

88+82+75+69+63+57+50+44+38+31+25+19+13+6 = 660 gigaparsecs

 

[CNBA3]

Then working my way from the inside out to get the number of planes that would fit these points between gigaparsecs by multiplying each layer with the sum value minus the previous inner value for a more spherical value:

• 660 single plane * 6 planes on direction = 3960 gigaparsecs
• 654 single plane * 13 planes on direction = 8502 gigaparsecs
• 641 single plane * 19 planes on direction = 12179 gigaparsecs
• 622 single plane * 25 planes on direction = 15550 gigaparsecs
• 597 single plane * 31 planes on direction = 18507 gigaparsecs
• 566 single plane * 38 planes on direction = 21508 gigaparsecs
• 528 single plane * 44 planes on direction = 23232 gigaparsecs
• 484 single plane * 50 planes on direction = 24200 gigaparsecs
• 434 single plane * 57 planes on direction = 24738 gigaparsecs
• 377 single plane * 63 planes on direction = 23751 gigaparsecs
• 314 single plane * 69 planes on direction = 21666 gigaparsecs
• 245 single plane * 75 planes on direction = 18375 gigaparsecs
• 170 single plane * 82 planes on direction = 13940 gigaparsecs
• 88 single plane * 88 planes on direction = 7744 gigaparsecs
• Total: 7744 + 13940 + 18375 + 21666 + 23751 + 24738 + 24200 + 23232 + 21508 + 18507 + 15550 + 12179 + 3960 = 229350 Gigaparsecs

Thoughts?

 

[CNBA3]

So I tried another method such as sphere packing which is finding how many smaller spheres you can pac into a larger spehere, so I had help with understanding it better with how many spheres you can fill with a diameter of one Gigaparsec into a larger sphere the size of the universe and I would get over 17155 Gigaparsecs

thoughts?

 

[CNBA3]

Bump

 

[Robo432343]

The observable universe is estimated to have a radius of about 46.5 billion light-years. One megaparsec (Mpc) is approximately equal to 3.26 million light-years. Therefore, you can calculate the size of the observable universe in megaparsecs by dividing its radius in light-years by the conversion factor.

46.5 billion light-years÷3.26 million light-years/Mpc46.5billion light-years÷3.26million light-years/Mpc

according to chatgpt

 

[CNBA3]

The observable universe is estimated to have a radius of about 46.5 billion light-years. One megaparsec (Mpc) is approximately equal to 3.26 million light-years. Therefore, you can calculate the size of the observable universe in megaparsecs by dividing its radius in light-years by the conversion factor.

46.5 billion light-years÷3.26 million light-years/Mpc46.5billion light-years÷3.26million light-years/Mpc

according to chatgpt

“ChatGPT” unfortunate. LoL

 

[CNBA3]

Bump

 

[CNBA3]

Bump