Jamesthetaker
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How do you calc feat of a character cutting a mountain in half?
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If there was no visual feat then how do we know the area of the cut?The equation for cutting is:
Width of the cutting surface (ie, thickness of the edge of the blade) = w
Area of the cut = A
Sheer strength of the material = s
Energy = w*A*s
Sheer Strength of the material? Can you give an exampleThe equation for cutting is:
Width of the cutting surface (ie, thickness of the edge of the blade) = w
Area of the cut = A
Sheer strength of the material = s
Energy = w*A*s
I think there was a calc for this and it got Low 7-B+, but for the method itself I don't actually know as I've never did a calc like this.How do you calc feat of a character cutting a mountain in half?
I'll try to find it.Can you provided a link to it?
No problem.Thank!
You can use the cross section of a cone. If you don’t know dimensions of the mountain, you can likely use the “small mountain” from here which has a diameter of 2180.2 m and height of 609.6 m making its cross section a triangle with an area of 664524.96m^2If there was no visual feat then how do we know the area of the cut?
Meant to write shear strength, my bad.Sheer Strength of the material? Can you give an example
Oh thanks.You can use the cross section of a cone. If you don’t know dimensions of the mountain, you can likely use the “small mountain” from here which has a diameter of 2180.2 m and height of 609.6 m making its cries section a triangle with an area of 664524.96m^2
Meant to write shear strength, my bad.
Here are some shear strengths for rocks