Feat Question

[Jamesthetaker]

How do you calc feat of a character cutting a mountain in half?

 

[Thelastmlg]

Not sure, I think we find the speed at which the halves moved and do KE, but I remember some sectional destruction calcs

 

[Blahblah9755]

The equation for cutting is:
Width of the cutting surface (ie, thickness of the edge of the blade) = w
Area of the cut = A
Shear strength of the material = s
Energy = w*A*s

 

[Jamesthetaker]

The equation for cutting is:
Width of the cutting surface (ie, thickness of the edge of the blade) = w
Area of the cut = A
Sheer strength of the material = s
Energy = w*A*s

If there was no visual feat then how do we know the area of the cut?

 

[WrongIdea21]

The equation for cutting is:
Width of the cutting surface (ie, thickness of the edge of the blade) = w
Area of the cut = A
Sheer strength of the material = s
Energy = w*A*s

Sheer Strength of the material? Can you give an example

 

[Kanogami]

How do you calc feat of a character cutting a mountain in half?

I think there was a calc for this and it got Low 7-B+, but for the method itself I don't actually know as I've never did a calc like this.

 

[Jamesthetaker]

Can you provided a link to it?

 

[Kanogami]

Can you provided a link to it?

I'll try to find it.

 

[Kanogami]

Nevermind, it was actually High 7-C, but this is it.

 

[Jamesthetaker]

Thank!

 

[Kanogami]

Thank!

No problem.

 

[Blahblah9755]

If there was no visual feat then how do we know the area of the cut?

You can use the cross section of a cone. If you don’t know dimensions of the mountain, you can likely use the “small mountain” from here which has a diameter of 2180.2 m and height of 609.6 m making its cross section a triangle with an area of 664524.96m^2

Sheer Strength of the material? Can you give an example

Meant to write shear strength, my bad.
Here are some shear strengths for rocks

 

[WrongIdea21]

You can use the cross section of a cone. If you don’t know dimensions of the mountain, you can likely use the “small mountain” from here which has a diameter of 2180.2 m and height of 609.6 m making its cries section a triangle with an area of 664524.96m^2

Meant to write shear strength, my bad.
Here are some shear strengths for rocks

Oh thanks.

 

[Jamesthetaker]

@Blahblah9755

So i have running into some problem lately. Firstly, i don't know which calculator i should used to give the same result for cross section above. Secondly, i don't know what is the units of the equation for cutting

 

[Blahblah9755]

Do you mean the result for the NnT calc? If so, that’s based on kinetic energy, so it’s not a calc of the cut itself but of the movement of the two halves. This can only be done if you know how far the mountain’s halves moved, and how quickly.
For units for cutting, the easiest way is to use m for thickness, m^2 for area, pascal for shear strength, and joules for energy (because a pascal is 1N/m^2 or 1J/m^3). Though, if you use google calculator it automatically calculates unit conversions as well.

 

[Jamesthetaker]

Hmm, this feat are entirely statement based so i don't know about how fast it is. If i know about the timeframe when the character swing their sword then does it count?

 

[Blahblah9755]

Probably not. The mountain only needs to move the width of the sword during the time of the swing.

 

[Jamesthetaker]

Hmm, this whole thing seem too complicated for a simple statement like that. I will request it in calc request thread instead.

Thank for your help anyway. I've learnt a new calc method so your effort wasn't wasted btw.