Depth of Craters formed from Explosions

[Antvasima]

Thank you very much for helping out so much DontTalk. You are awesome as always.

 

[Arc7Kuroi]

Not sure if the explosion yield page or the calculations page is more appropriate, but I will add it somewhere.

So, I was looking back at this, and the units you have to use for the depth formula for craters larger than 10 km in diameter has to be inputted in with units of km.

Aka this depth equation D = 1.43493*R^.564103 requires the units of R to be in km, because there is some units baked into the constant (since we have radius to a non unity exponent, the ~1.4 constant carries units of km^.44 to balance the radius term carrying units of km^.56 to have a length unit result). I don't know if you added this to any page yet, but figured I'd let you know now.

TLDR; the depth of a crater with a diameter above 10 km is D = 1.43493*R^.564103, where R is in km and the resulting answer D is also in km. The volume, assuming a paraboloid is V = 2.25398*R^2.564103, where R is in km and the resulting answer V is in km^3.

 

[Antvasima]

So, I was looking back at this, and the units you have to use for the depth formula for craters larger than 10 km in diameter has to be inputted in with units of km.

Aka this depth equation D = 1.43493*R^.564103 requires the units of R to be in km, because there is some units baked into the constant (since we have radius to a non unity exponent, the ~1.4 constant carries units of km^.44 to balance the radius term carrying units of km^.56 to have a length unit result). I don't know if you added this to any page yet, but figured I'd let you know now.

TLDR; the depth of a crater with a diameter above 10 km is D = 1.43493*R^.564103, where R is in km and the resulting answer D is also in km. The volume, assuming a paraboloid is V = 2.25398*R^2.564103, where R is in km and the resulting answer V is in km^3.

@DontTalkDT