• This forum is strictly intended to be used by members of the VS Battles wiki. Please only register if you have an autoconfirmed account there, as otherwise your registration will be rejected. If you have already registered once, do not do so again, and contact Antvasima if you encounter any problems.

    For instructions regarding the exact procedure to sign up to this forum, please click here.
  • We need Patreon donations for this forum to have all of its running costs financially secured.

    Community members who help us out will receive badges that give them several different benefits, including the removal of all advertisements in this forum, but donations from non-members are also extremely appreciated.

    Please click here for further information, or here to directly visit our Patreon donations page.
  • Please click here for information about a large petition to help children in need.

Can you find Wavelength without Frequency?

3,777
326
Say you want to find the wavelength of a sound-wave, but you don't have a frequency, what would be the best method to find the wavelength height?
 
I heard that you can get frequency from 1 divided by time, would the time be refered to how long the sound continued to propagate?

here is the calculator

 
Say you want to find the wavelength of a sound-wave, but you don't have a frequency, what would be the best method to find the wavelength height?
Wavelength and height are two different things. Wavelength is the length of the wave. When you say height, I believe what you're talking about is amplitude. Think about dropping a pebble into a pond. Amplitude is how tall the ripples are, wavelength is the distance from one ripple to the next.
 
Wavelength and height are two different things. Wavelength is the length of the wave. When you say height, I believe what you're talking about is amplitude. Think about dropping a pebble into a pond. Amplitude is how tall the ripples are, wavelength is the distance from one ripple to the next.
yeah, I kind of figured that out later, thanks, Is there a way to measure the distance of a ripple from a shout? Would a air ripple be calculable?
 
measure the distance of a ripple from a shout
distance = speed of sound * time

the time it takes for the ripple to travel from the source to the observer can be measured by timing the interval between the shout and the arrival of the ripple

Okay, so is that from the origin point of a wave to it’s destination?
no, the period of a wave is the time it takes for one complete cycle of the wave to occur. the wave would have to travel back to its origin point before the period would be complete. what you are referring to is the wavelength
 
distance = speed of sound * time

the time it takes for the ripple to travel from the source to the observer can be measured by timing the interval between the shout and the arrival of the ripple


no, the period of a wave is the time it takes for one complete cycle of the wave to occur. the wave would have to travel back to its origin point before the period would be complete. what you are referring to is the wavelength
Okay, I think I understand, so like say the time it takes is 2.5 seconds to reach the target and travels at the speed of sound, right?

Okay, i think i get it, so the period would be double what the distance would be from what would be found on top right?
 
Okay, I think I understand, so like say the time it takes is 2.5 seconds to reach the target and travels at the speed of sound, right?

Okay, i think i get it, so the period would be double what the distance would be from what would be found on top right?
yes
 
Frequency is inversely proportional to time so if you have the time then you could calculate the wavelength without an exact frequency
 
Frequency is inversely proportional to time so if you have the time then you could calculate the wavelength without an exact frequency
Okay, thanks, I guess the time is around 10.5 seconds long, 2.5 seconds for the sound wave to reach the the destination and 8 seconds for the sound to affectively destroy the target.
 
Okay, thanks, I guess the time is around 10.5 seconds long, 2.5 seconds for the sound wave to reach the the destination and 8 seconds for the sound to affectively destroy the target.
f = 1/t

t = time which is 10.5s
f = 1/10.5
the frequency would be 0.0952381 s^-1

Since you're calculating soundwaves then the velocity would be 343 m/s
λ = velocity/frequency = 343/0.0952381 = 3601.5m ≈ 3.6km
 
Last edited:
Here's another formula for wavelength:

λ = h/mv

m = mass
v = velocity
h = Planck's constant (6.626 x 10^-34)

Hope this helps
 
f = 1/t

t = time which is 10.5s
f = 1/10.5
the frequency would be 0.0952381 s^-1

Since you're calculating soundwaves then the velocity would be 343 m/s
λ = velocity/frequency = 343/0.0952381 = 3601.5m ≈ 3.6km
This isn't really helpful. T actually needs to be the time period of one wave, i.e the time it takes for one wavelength to repeat. NOT just however long the sound was going for.

Here's another formula for wavelength:

λ = h/mv

m = mass
v = velocity
h = Planck's constant (6.626 x 10^-34)

Hope this helps
deBroglie wavelength is typically only used for singular particles like electrons (hence why mass is involved) compared to sound waves which move lots of air molecules in pressure waves.
 
This isn't really helpful. T actually needs to be the time period of one wave, i.e the time it takes for one wavelength to repeat. NOT just however long the sound was going for.


deBroglie wavelength is typically only used for singular particles like electrons (hence why mass is involved) compared to sound waves which move lots of air molecules in pressure waves.
Okay, from what I understand it would be a sound wave to travel from the source and back right? So the time would be 5 seconds.
 
so with that (f = 1/5 = .2 s)

and applying that to wavelength (343/.2 = 1715 meters)
 
This isn't really helpful. T actually needs to be the time period of one wave, i.e the time it takes for one wavelength to repeat. NOT just however long the sound was going for.


deBroglie wavelength is typically only used for singular particles like electrons (hence why mass is involved) compared to sound waves which move lots of air molecules in pressure waves.
Oh yeah, right, forgot to mention the deBrogile equation is only for singular particles

I mean, you could search up how long it takes for that particular acoustic wave to repeat
 
Okay so what i can get with the recommended formulas, i would get this.

(8575 dB)^2 * (1/2) * 343 m/s * .2 Hz
 
Back
Top