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Huh, 1 High 1-B is infinite dimension on itself, there are infinite amount of High 1-B, thus it is Infinite*(High 1-B) = Infinite*InfiniteI don't think the term of infinite*infinite is objectively correct, just imagine the baseline High 1-B is an infinite-dimensional universe, if there's an infinite amount of them then their difference would be like Low 2-C vs 2-A, an unquantifiable level of superiority (because we can't exactly quantify the distance between universes). It's still High 1-B though.
Infinite*infinite High 1-B would be like an infinite*infinite amount of dimensions, which is still infinite. Because infinite is still countable, you can biject infinite*infinite with infinite with Cantor's diagonal argument. Saying infinite universes of High 1-B = infinite*infinite is kind of weird, since that's like saying 2-A is infinite*4 or infinite*(Low 2-C). Infinite dimensions isn't High 1-B and 4 dimensions isn't Low 2-C, anyway.Huh, 1 High 1-B is infinite dimension on itself, there are infinite amount of High 1-B, thus it is Infinite*(High 1-B) = Infinite*Infinite
What's your pointYes, infinite*infinite is still infinite, thus still High 1-B, that what i said, but it would be > Baseline High 1-B
Okay...?Yes, infinite*infinite is still infinite, thus still High 1-B, that what i said, but it would be > Baseline High 1-B
I know this is kinda old but isn't it infinite^2?Infinite High 1-B is still High 1-B, just infinitely higher than baseline. Because Infinite High 1-B is just Infinite*Infinite. In order to be Low 1-A it need to be uncountable infinite or infinite^infinite
Infinite^2 still = infiniteI know this is kinda old but isn't it infinite^2?
But doesn't the Ch says 2^infinite=Aleph1 though?Infinite^2 still = infinite
2^infinite =/= infinite^2But doesn't the Ch says 2^infinite=Aleph1 though?
Uhh no i wasnt talking about multiplication.2^infinite =/= infinite^2
You confusing ^ with x
Indeed infinite x 2 = 2 x infinite but ^ is way different
Anyways in a word of infinite it would be infinite^infinite? I heard you do it like 2^infinite + in the continuum hypothesis it was something like that except in a form of a aleph, can you clarify some stuff for me?2^infinite =/= infinite^2
You confusing ^ with x
Indeed infinite x 2 = 2 x infinite but ^ is way different
Since im pretty sure continuum hypothesis says Aleph null^2 is the correct phrase.2^infinite =/= infinite^2
You confusing ^ with x
Indeed infinite x 2 = 2 x infinite but ^ is way different
Infinite^infinite = uncountable infinite which mean Aleph 1.Anyways in a word of infinite it would be infinite^infinite? I heard you do it like 2^infinite + in the continuum hypothesis it was something like that except in a form of a aleph, can you clarify it to me?
Yeah ik that's why im asking if infinite^2 or aleph null^2 is valid since i heard it's the correct phrase of the continuum hypothesis.Infinite^infinite = uncountable infinite which mean Aleph 1.
In continuum hypothesis, you can see it in wikipedia. It is long to say but it is 2^Aleph 0 = Aleph 1. Aleph 0 is countable infinite which is natural number
So i can't use the term infinite^2? But i can use aleph null^2? So i need to clarify it then?Aleph 0^2 =/= infinite^2. Aleph 0 is a set of natural number^2. Infinite is not a set of number
Hmm, i don't remember Aleph 0^2 = Aleph 1. 2^Aleph 0 sure = Aleph 1, continuum hypothesis, ZFCSo i can't use the term infinite^2? But i can use aleph null^2? So i need to clarify it then?
So infinite^infinite and aleph null^2 for aleph1are the correct phrase then?
Yeah i meant that, so i take that as a yes then?Hmm, i don't remember Aleph 0^2 = Aleph 1. 2^Aleph 0 sure = Aleph 1, continuum hypothesis, ZFC
Uh oh yes. They both cardinality of the natural numberThere is no difference between Aleph 0 and Infinity, they both have the exact same cardinality.
Meh so what is the point here?There is no difference between Aleph 0 and Infinity, they both have the exact same cardinality.
Yes, but if you want more informations, then research is in order......Yeah i meant that, so i take that as a yes then?
Yes, they areMeh so what is the point here?
is it that 2^infinity and 2^aleph null=Aleph 1
Are both valid in the Continuum hypothesis?
Ok...Yes, but if you want more informations, then research is in order......
The other guy said infinite^infinite is also Aleph1 is it something that is different from the continuum hypothesis?Yes, they are
SoIf you assume the continuum hypothesis is true, then infinite^infinite should be Aleph-1 in cardinality
Nah, infinite^infinite is the easiest way to understand uncountable infinite, which mean Aleph 1, or infinite recursion of infinityThe other guy said infinite^infinite is also Aleph1 is it something that is different from the continuum hypothesis?
Alright.