A heat blast that burned a bunch of trees and I want to know how to calculate It

[JustANormalLemon]

I want to found the AP needed to generate a heat wave that burned a bunch of trees only leaving It's now dark bodies without any leaf's, tHere is only the aftermach of the heat wave but It's easy to get the radius thanks to the burned trees then selfs, but other then the trees there is no damage

How should I calculate this heat explosion?

The diameter of the Heat wave is 25.52 meters(Radius of 12.76) and the Heat traveled trough the air burning all the trees on It's path

 

[Imaginym]

Bumping for interest.

 

[BreezeHM]

Should make a calc request for things like this but I'll attempt it.

Determining the Area
First we'll assume the diameter of the Heat Wave is the same as the trees.
I'm gonna assume a circle, using the radius of 12.76 Meters to determine the area. You can fix it after if needed.
Using the Area of a circle we get, 511.51 m^2

Determine the amount of trees.
Using this Tree calculator and their websites standards for white oak tree, there is 871 trees per acre. (2ft between rows, 25 ft between trees)
1 acre = 4046.86 m^2

Number of acres = (Number of square meters) / (1 acre / 4046.86 square meters)

Number of acres = 511.51 square meters / (1 acre / 4046.86 square meters)

Number of acres = 511.51 / 4046.86

511.51 m^2 = 0.1265 acres


Number of trees in 0.1265 acres = (Number of acres) * (Number of trees per acre)

Number of trees in 0.1265 acres = 0.1265 acres * 871 trees/acre

Number of trees in 0.1265 acres = 110.17 trees

Mass of Each Log
Mass of Oak Wood is 26,582 kg per tree.
Moisture Content
Moisture Content of Oak wood is 75%
Removing Moisture from Wood
For this, we'll use the latent heat of vaporization for water (2,257 J/g)
First we'll convert the moisture content to grams by multiplying it by the mass.
75% x 26582000 grams (26,582 kg) = 19936500 grams
Now the Energy Required to remove the moisture from the wood
Joules = Moisture Content * Latent Heat Vaporization
Joules = 19936500 grams * (2,257 J/g) = 44 996 680 500 joules

Carbonization
Oak wood has a heat capacity of 2380 j/kg°C
Oak Tree has a temperature of 55°F thats 12.78°C
Tree logs go black at around 600 degrees Celsius
(ΔT) = T1 - T2
(ΔT) = 600 - 12.78 = 587.22°C
Energy = Mass (kg) × Specific heat capacity (J/kg°C) × ΔT (°C) × 1,000 (to convert grams to kilograms)
Energy = 26582 kg x 2380 j/kg°C x 587.22°C = 37 279 570 184

Pre Final Tally
44 996 680 500 + 37 279 570 184 =
82,276,250,684

So It takes 82,276,250,684. Joules to turn one tree black.

Since there is 110.17 trees, multiply it by that.

That gives us 9.0643745e+12 Joules

Tiering System Conversion
9.0643745e+12 Joules = 2.17 Kilotons

(Low 7-C, Small Town level)

I'm not a calc group member so don't blindly believe this calculation is correct. But, if one doesn't come into this thread to correct me, you can send it for an evaluation.

 

[JustANormalLemon]

Should make a calc request for things like this but I'll attempt it.

Determining the Area
First we'll assume the diameter of the Heat Wave is the same as the trees.
I'm gonna assume a circle, using the radius of 12.76 Meters to determine the area. You can fix it after if needed.
Using the Area of a circle we get, 511.51 m^2

Determine the amount of trees.
Using this Tree calculator and their websites standards for white oak tree, there is 871 trees per acre. (2ft between rows, 25 ft between trees)
1 acre = 4046.86 m^2

Number of acres = (Number of square meters) / (1 acre / 4046.86 square meters)

Number of acres = 511.51 square meters / (1 acre / 4046.86 square meters)

Number of acres = 511.51 / 4046.86

511.51 m^2 = 0.1265 acres


Number of trees in 0.1265 acres = (Number of acres) * (Number of trees per acre)

Number of trees in 0.1265 acres = 0.1265 acres * 871 trees/acre

Number of trees in 0.1265 acres = 110.17 trees

Mass of Each Log
Mass of Oak Wood is 26,582 kg per tree.
Moisture Content
Moisture Content of Oak wood is 75%
Removing Moisture from Wood
For this, we'll use the latent heat of vaporization for water (2,257 J/g)
First we'll convert the moisture content to grams by multiplying it by the mass.
75% x 26582000 grams (26,582 kg) = 19936500 grams
Now the Energy Required to remove the moisture from the wood
Joules = Moisture Content * Latent Heat Vaporization
Joules = 19936500 grams * (2,257 J/g) = 44 996 680 500 joules

Carbonization
Oak wood has a heat capacity of 2380 j/kg°C
Oak Tree has a temperature of 55°F thats 12.78°C
Tree logs go black at around 600 degrees Celsius
(ΔT) = T1 - T2
(ΔT) = 600 - 12.78 = 587.22°C
Energy = Mass (kg) × Specific heat capacity (J/kg°C) × ΔT (°C) × 1,000 (to convert grams to kilograms)
Energy = 26582 kg x 2380 j/kg°C x 587.22°C = 37 279 570 184

Pre Final Tally
44 996 680 500 + 37 279 570 184 =
82,276,250,684

So It takes 82,276,250,684. Joules to turn one tree black.

Since there is 110.17 trees, multiply it by that.

That gives us 9.0643745e+12 Joules

Tiering System Conversion
9.0643745e+12 Joules = 2.17 Kilotons

(Low 7-C, Small Town level)

I'm not a calc group member so don't blindly believe this calculation is correct. But, if one doesn't come into this thread to correct me, you can send it for an evaluation.

JustANormalLemon/sandbox/TABS

vsbattles.fandom.com

Well, there is only 12 trees, their leafs all burned out and they are all black, but really thank You, I will use that to make the calc my self, this will help a lot

 

[JustANormalLemon]

82,276,250,684

So... this times 12

987315008208 joules

So Low 7-C still... somwhow lol

 

[BreezeHM]

So... this times 12

987315008208 joules

So Low 7-C still... somwhow lol

No 987315008208 Joules is 235 Tons
8-A, Multi-City Block

 

[JustANormalLemon]

No 987315008208 Joules is 235 Tons
8-A, Multi-City Block

oh, okay, makes more sense