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Another tier question

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If there are an infinite number of high 1-B structures that exist as their own separate space-time continuums, which in turn all exist as an infinitesimal part of a larger space-time continuum, would this be low 1-A?
 
And if the structures in question are low 1-A, does the larger structure become 1-A?
No, 1-A mean beyond all definition of dimension, even if you try stacking dimension upon dimension you still can't reach it, larger than Low 1-A is just still higher than baseline Low 1-A without more context
I'm not entirely sure what that means in this context.
It is math so....uh....well, just ignore it, unless you want to study math. Simplify it, it mean 2^infinite = Aleph 1 (uncountable infinite), Aleph 1 of dimensional layer is Low 1-A. so next is 2^Aleph 1 = Aleph 2 i think, which is one of requirement for 1-A
 
No, 1-A mean beyond all definition of dimension, even if you try stacking dimension upon dimension you still can't reach it, larger than Low 1-A is just still higher than baseline Low 1-A without more context
"Characters who can affect objects with a number of dimensions equal to the cardinal aleph-2, which in practical terms also equals a level that completely exceeds Low 1-A structures to the same degree that they exceed High 1-B and below."

Idk, definitely sounds like it'd be 1-A through stacking L1-A structures if stacking H1-B structures in the same manner would be L1-A.

It's bassically infinities of infinities of infinities of infinities then go on infinitely of a said infinite.
I think I'm even more confused than I was before.
 
I think I'm even more confused than I was before.
[/QUOTE]
Idk how this is confusing but bassically 2^infinite=aleph 1
This is bassically a infinite amount of infinite of infinite of infinite of infinite(go on infinitely) then after that you would reach aleph 1 like i said to reach aleph 2 you would need to do a simillar equation which is 2^uncountable infinite so you need a uncountable infinite amount of uncountable infinite of uncountable infinite of uncountable infinite(go on for a uncountable infinite amount of times) then you do this again on the next stage until you reach a limit ordinal.
 
Idk, definitely sounds like it'd be 1-A through stacking L1-A structures if stacking H1-B structures in the same manner would be L1-A.
Another completely misunderstanding of the tiering system. High 1-B is infinite stacking of dimensions, Low 1-A is uncountable infinite stacking of dimension, uncountable is already unreachable by itself. 1-A is even beyond that, mean beyond even uncountable itself
 
From what I understand the way that larger cardinal numbers transcend is similar (cmiiw)

This can be extrapolated to larger cardinal numbers as well, such as aleph-3, aleph-4, and so on, and works in much the same way as 1-C and 1-B in that regard.
 
And if the structures in question are low 1-A, does the larger structure become 1-A?
A few days late but i'll try to answer and explain this with the most simple term possible.

It wouldn't be 1-A since it wouldn't equate to 2^aleph1

The 1st example simply became aleph 1 because of 2^aleph 0(infinite^infinite) which bassically has the necessary math to be aleph 1 but in this case it can't reach aleph 2 because it can't equate to aleph 2 or 2^aleph 1 because of the fact that it is aleph 1^aleph 0 in which you need a mathematics that equate to 2^aleph 1 in simple terms you need aleph 1^aleph 1 and what you gave is aleph 1^aleph 0 if im not wrong.
 
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