I looked up some geology stuff, and it looks like Brazil has very deep bedrock and pretty sandy soil, so atomic annihilation for sand might be better than the rock/concrete one here. I’m using
silicon dioxide, and the method
here (which is what we use for our subatomic destruction of water).
Silicon dioxide has a molecular mass of 60.08 amu, silicon dioxide has 30 protons and 30 neutrons
Mass of a proton is 1.00728amu
Mass of a neutron is 1.00867amu
That gives 60.4785
60.4785-60.08= 0.3985amu
0.3985 amu/molecule* 1.66053893E-27kg/amu= 6.61724764e-28kg
E= 6.61724764e-28kg*c^2= 5.94728559e-11J/molecule
5.94728559e-11J/molecule*6.022e+23molecule/mol= 3.5820501e+13 J/mol
Silicon dioxide has a molar mass of 60.08 g/mol, and a density of 2.65g/cc. 2.65/60.07= 0.04410785619mol/cc
3.5820501e+13 J/mol * 0.04410785619mol/cc= 1.57996551e+12 J/cc
So, using the same volume,
2.72504545568e+24cc*1.57996551e+12 J/cc= 4.30547783e+36 Joules, or
Large Planet level