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Destroying a Mahlo Cardinal amount of 3-D universes. Note that you're not destroying higher dimensional realms here but only 3-D. Iirc Mahlo Cardinal is only tier 0 if its the amount of dimensions.
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What tier is this feat?
- Thread starter Lord_Zeref_Dragneel
- Start date
Cat275
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Tier 0, Aleph omega amount of universes are high1-B
Then we have the bigger aleph omega sequence or the limit cardinals of aleph which can go to atleast H1-A.
Inaccessible and such are 0
And yes the vsb system uses inaccessible as H1-A but the example was very faulty since even the alephs can reach tier 0 based from what i see.
(As an example check self reference engine thread though do keep in mind that this isn't related to the question and this example is only good if they actually tiered it 0.)
Then we have the bigger aleph omega sequence or the limit cardinals of aleph which can go to atleast H1-A.
Inaccessible and such are 0
And yes the vsb system uses inaccessible as H1-A but the example was very faulty since even the alephs can reach tier 0 based from what i see.
(As an example check self reference engine thread though do keep in mind that this isn't related to the question and this example is only good if they actually tiered it 0.)
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- Thread starter
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I see. I completely forgot about the Alephs and how far inaccesible and mahlo is compared to uncountable infinite lmao
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Is it true that destroying an uncountable infinite amount of uncountable infinite sized 4-D universes is equivalent to 6-D? If yes, is it just baseline 6-D or infinite 6-D?
Cat275
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Debatable it can be 5d or 6d need a little bit more of context i suppose, though in the case that it was 6d it would be baseline.
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He said Aleph omega universe not Aleph omega dimension
Cat275
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Your saying Aleph omega universes is 1-A+?
Cat275
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Pretty much, then we can create aleph omega^omega then aleph omega^omega^omega and such.
Cat275
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Wdym? Well you can go beyond aleph omega, if you follow the well ordering theorem and know omega a little bit you will understand that omega^omega will have a higher cardinallity than omega, what this means is that we can create aleph omega^aleph omega and make a bigger sequence of aleph omega.
This new aleph omega should be 1-A+ even if it only has a universe amount of it.
(Then after that we can go even bigger)
The final step of this successor operation of omega are limit cardinal alephs some example of this are:
Suppose lambda is a limit ordinal then aleph lambda is a limit cardinal.
(What this means is that this new cardinal is unobtainable by any successor operation the alephs below has, it doesnt mean it is a form of indescribabillity though so it may or may not be a inaccessible cardinal.)
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Its still 1-A+
It is. Any aleph-2 amount of something (such as points) is already bigger than any Low 1-A quantity. Thus, Aleph-Omega universes would also be 1-A+
Cat275
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Aleph 2 is just aleph 1^aleph 1.
It is not a limit cardinal to aleph 1.
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Eh, really? But I hear different thing about this before so I presume Aleph omega for dimension and Aleph omega Universes is different
Cat275
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That is the point.
I mean alephs usage in the tiering system is already so wrong as the continuum hypothesis goes higher and so 2 infinite r>f hierarchy isn't supposed to be 1-A+.
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I thought that
Aleph 0 amount universes = infinite universes (2A)
Aleph 1 amount universe = uncountable infinite universes = 5D construct = low1-C
Aleph 2 amount universes = 6D = low 1-C
And continue for other Alephs till
Aleph omega universes = Infinite D = High 1-B
am I completely mistaken here?
Aleph 0 amount universes = infinite universes (2A)
Aleph 1 amount universe = uncountable infinite universes = 5D construct = low1-C
Aleph 2 amount universes = 6D = low 1-C
And continue for other Alephs till
Aleph omega universes = Infinite D = High 1-B
am I completely mistaken here?
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Aleph-2 universes would be 1-A
Everything from 11-B to Low 1-A is R amounts of something, and Aleph-2 > R
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Okay, then I really am wrong, huh? Sorry Darkmash
Cat275
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Alright after looking at the continuum hypothesis and some fair amount of comparison, i kinda agree now.
(since H1-B is around infinite * uncountable infinite in a amount of dimensions and it's quality and L1-A would be Uncountable infinite * Uncountable infinite.
Note:I wasn't talking about the cardinallity atleast that wasn't most of the point here.)
Well atleast something like Aleph omega^Aleph omega^Aleph omega is 0 to me now.
(Or atleast aleph omega^aleph omega^aleph omega^aleph omega.)
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