Kurama's strength can be said to be equivalent to 5 beasts, so it can be assumed that the Bijuu Obito who absorbs 7 Bijuu is already comparable to Kurama + Gyuki which means that Bijuu Obito only gets 50% power from the full power of the Bijuu that has Kurama + Gyuki because the assumption is that the Bijuu Obito is equal to kurama+gyuki.
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https://cdn.**********.com/attachments/1014801570019426358/1018856121030688808/naruto_571_12.jpg
Using linear calculations to measure the Juubi's strength
-Juubi is formed from 9 biju+gedo mazo shells
-Juubi absorbed by Obito is a Juubi that takes a full 7 biju + small flakes from Kurama + Gyuki
-If using Biju Dama Fighting Calculation (Chap 570)
-(1/2 Kurama = 5 Biju, 1 Kurama = 10 Biju?)
-This is a feat from naruto who has 1/2 of Kurama's chakra can withstand even more powerful than 5 biju
-Assuming that Biju 1-7 have the same strength is not unusual because they can form a tailed beast of the same size and state by shukaku if the tail also determines strength
-Gyuki alone can hold 2 tailed beasts alone, he can be equal to 2 tailed beasts if he can. If you add up using rough calculations, Kurama can be considered stronger than all the tailed beasts, especially with the tail statement affecting the strength of the tailed beasts, which is 10 beasts, the Juubi requires 19 Biju in strength, with the benchmark 1 earlier. If in total obito has 7 beasts + a little power from Kurama and gyuki let's assume the Chakra reaches 60% of the size of one beast
Juubi Obito = 7.6 out of 19 beasts to reach the perfect Juubi
Juubi Obito = 40% of Juubi Fullpower
This is the result if we want to use the calculation linearly.
Oh ya, is there any reason other than not using linear calculations/bad assumptions?
