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Tier for vaporizing an average sized iceberg

Kaltias

VS Battles
Retired
19,122
6,334
^ Title.

And the temperature of air is low enough to freeze seawater in that specific case
 
https://www.backcountrysafaris.com/kenai-fjords-national-park/icebergs.php

Here's for the size of the iceberg

Height 51'-150'(16-45 m) Lenght 201'-400'(61-122 m)

Would be the average

The temperature needed to freeze seawater is -1.9┬░C (28.4 ┬░F) according to this

Density of an iceberg is 10% 920 kg/m^3 (the part above water surface) and 90% 1025 kg/m^3. Internal temperature of icebergs can reach -15/-20 ┬░C and average weight is between 100,000 and 200,000 tons (Source)

Here's how to calc it

Now I don't have time to do the math myself though, but these values should help
 
So

Mass: 150,000 tons = 150,000,000 Kg

Sepcific heat of ice: 2.09 J/g*┬░C = 2090 J/Kg*┬░C

Assuming -15┬░C as the starting temperature

From -15┬░C to 0:

q= 150,000,000*2090*(0 - (-15)) = 4,702,500,000,000 J

From ice to water

Heat of fusion: 334 J/g = 334000 J/Kg

q= 150,000,000*334000 = 50,100,000,000,000 J

From 0┬░C to 100┬░C

Specific heat of water: 4.18 J/g*┬░C = 4180 J/Kg*┬░C

q= 150,000,000*4180*(100 - 0)= 62,700,000,000,000 J

From water to Steam

Heat of vaporization: 2257 J/g = 2257000 J/Kg

q= 150,000,000*2257000 = 338,550,000,000,000 J

4,702,500,000,000 + 50,100,000,000,000 + 62,700,000,000,000 + 338,550,000,000,000 = 456,052,500,000,000 J, 108999.16347992475 tons, High 7-C

That is, if I didn't mess up anywhere
 
Nice. I'll count the number of shots used to do that as soon as I can, so we can get the AP for the individual attacks
 
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