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The Eminence in the Shadows CRT





It’s a torrent of magic, whirling as it floods out of Shadow’s body.



Swallowed up by the magic, the rain stops.



“This can’t… Is this even real…?!”



“This is…impossible.”



The unimaginable force stops Iris and Beatrix in their tracks.



With power like this, annihilating the entire stadium would have been trivial for him.



Iris, Beatrix, and the spectators are all equally helpless in the face of such might.



“Why would I need to flee…?”



Nobody can possibly stop him. They have no choice but to acknowledge that.



“Why…?” asks Iris, her voice shaking. “If you had all that power…you could have killed us whenever you wanted.”



“…I achieved my objective. I have no interest in your lives… The only ones we butcher are our enemies…”



Shadow looks at Iris as he makes his magic converge on his sword.



“Make sure you remember…who your true enemy is.”



With that, Shadow releases the energy into the sky.



A blinding light floods the stadium and spreads out across the entire capital as it blots out the heavens and blasts away the rain clouds.



When it fades, all that’s left is a clear blue sky.



Shadow is nowhere to be seen.



The clouds, the rain, the lightning, and Shadow himself… It’s like they were never even there. ~ Volume 2, final chapter.



Kinetic Energy = MV^2



Cumulonimbus and nimbostratus clouds are the types that bring us the majority of our rain. A density of a cloud is 1.003 kg/m^3. [1] Timeframe = 200/4 = 50 m/s. [2]


The average is around 12,200 meters [1]. It has a radius of 20000 meters.



V = (3.141592653589793238462643383279502884197169399375105820974944592307816 * 20,000)^2 * 12200





3,947,841,760.435743447499999999999999999999999999999999999999999999999999999991813 * 12,200 = 48,163,669,477,316.0700594999999999999999999999999999999999999999999999999999999001186 m^3



48,163,669,477,316.0700594999999999999999999999999999999999999999999999999999999001186 * 1.003kg = 48,163,669,477,316.0700594999999999999999999999999999999999999999999999999999999001186 * 1.003kg = 48,308,160,485,748.018269678499999999999999999999999999999999999999999999999999899818955



48,163,669,477,316.0700594999999999999999999999999999999999999999999999999999999001186 * 1.003kg = 48,308,160,485,748.018269678499999999999999999999999999999999999999999999999999899818955 * (50)^2.



377,407,503,794,910,000,000 translates to 0.090202558268382 Teratons Of TNT. (I probably forgot to divide by 2 here. If so, 0.045 teratons, still 6-C so its irrelevant.)

380000000000000000000000000



6-C (Island level) FTL+ speeds.


[1] https://www.usgs.gov/special-topics.../science/how-much-does-a-cloud-weigh#overview (The government said so, trust the government 🙃)


[2] https://www.researchgate.net/figure...-used-by-i-the-United-King-dom_tbl1_324562206



So in this video, Shadow covers the entire solar system in 1/60th of a frame or 16.67 entirely (20 milliseconds rounded up)
IctlnoX.png


The light seems to be in a radius so V = 4/3πr^2
It is compared to the Sun with a line:
aTSMAiO.png


The Sun emits 3.828 × 10^26 watts / 1000 = 380000000000000000000000 * 20 milliseconds = 7600000000000000000000000 joules in a millisecond to cover the solar system

It is covering the entire solar system
KbGjCXM.png

The whole concept of an "edge" is somewhat inaccurate as far as the solar system is concerned, for there is no physical boundary to it - there is no wall past which there's a sign that says, "Solar System Ends Here." There are, however, specific regions of space that include outlying members of our solar system, and a region beyond-which the Sun can no longer hold any influence." - The Edge of the Solar System (2006)
So assuming this, valid boundary region for the "edge" of the solar system is the heliopause. It is a fluctuating boundary that is estimated to be approximately 17.6~ billion miles (122 A.U.) away.

The density of the energy emitted can now be calculated.
Radius of a solar system = 122 * 149.6 * 10^9.
Volume = 3/4πr(1.8292*10^13)^3
Energy density = 7.656×10^27 joules/5.169×10^40 cubic meters


Total energy needed≈1.479×10^−12 joules per cubic meter×5.169×10^40 cubic meters

Energy needed for 1 millisecond 7.655×10^28 joules.

Total energy for 53 seconds = 4.057×10304.057×10^30 or 4.18036×10^34 J (joules)

201.4 * 10^26 / 4.18036×10^34.

This attack was 2.0757825×10^6 stronger than the stronger than the Sun for its entire duration or 3.9245155×10^7 for 1 second.

Cid Kagenou is large planet (5-A) or 5-B as a lowball.
He can in fact destroy the planet, as he said.
 
Also I forgot to mention. He placed a barrier on the world and another on around the opponent and himself and on himself again:

7yGL1tc.png

p6pGtjD.png

RsgBpMp.png

jJI1CyK.png


He wouldn't of placed 3 barriers if he was not capable of destroying the world, he tanked his own attack too. 5-A, likely higher. Due to 2 barriers, we were not able to see any destructive power.
 
Last edited:
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By the calculation members. Check in here.
 
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