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What would be the attack potency if one can be able to destroy 10% of the solar system?
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Solar System Attack Potency question
- Thread starter UglyKittyCat238
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Oliver_de_jesus
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the 10% of mass of Solar System or 10% space and mass?
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- Thread starter
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What would be the answer to both?
Oliver_de_jesus
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The mass alone is 13.7 Tenatons. (Small Star)
the mass and space would be 2.277 Foe. (Large Star)
I may be wrong because it only takes 10% of the values of the sun(+the mass of other planets) and the solar system
the mass and space would be 2.277 Foe. (Large Star)
I may be wrong because it only takes 10% of the values of the sun(+the mass of other planets) and the solar system
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- Thread starter
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Thanks, quick question what does it mean by both space and mass?
Oliver_de_jesus
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The space between planets is about 100,000 times larger than all the planets and the sun combined.
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- Thread starter
- #7
Ok thanks. First time I'm hearing about the concept of destroying space. Quick question, how would the space in question be able to be destroyed?
Oliver_de_jesus
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I do not mean space literally, but the distance in space between two celestial bodies
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Oh I see, so it means being able to destroy the celestial bodies at once even with the distance?
Oliver_de_jesus
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Ok thanks
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Our solar system tier is based on causing a explosion that goes from the sun to neptune and destroys it, so i think in this case it would be 10% of it, but idk if that would include the bounder energy being planet level unless there is a planet there, if we don't assume, it would be just a explosion size valc and might be only small star level, if we do then is probably large star level
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Eh, no, the mass alone would be comprised of the Sun, which has a GBE of 5.693e+41 J or roughly 137 tenatons of TNT (4-C, Star level)
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Maybe assume 10% of the explosive radius (That'd be the Sun-to-Neptune distance) and use the GBE of the closest planet that lies out that far?
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Yeah i was trying to word like that
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Okay so...
Sun-to-Neptune distance is 30.1 AU. 10% of that is 3.01 AU. Closest planet in proximity is Mars at 1.5 AU. We'll just assume that it still has enough energy to destroy Mars up that far.
3.01 AU is roughly 4.5029e+11 meters. This is our explosion radius.
GBE of Mars needs to be found first.
GBE= (3G(M^2))/5R
Mars has a radius of 3389.5 km or 3389500 m, and a mass of 6.39e+23 kg. Gravitational constant is 6.6704e-11 N⋅m^2⋅kg^−2
GBE of Mars= (3 * (6.6704e-11) * (6.39e+23^2) ) / (5 * 3389500)= 4.8213561e+30 J
Reverse-inverse square law for finding out power of explosion at epicenter for cosmic bodies time.
Energy of Explosion at Epicenter = 4 * U * (Er/Tr)^2, where U is GBE of the target body, Er is the Explosion Radius and Tr is the target's radius.
E = 4 * 4.8213561e+30 * (4.5029e+11/3389500)^2= 3.4036315e+41 J or 81.34874522 tenatons of TNT (Low 4-C, Small Star level+)
Sun-to-Neptune distance is 30.1 AU. 10% of that is 3.01 AU. Closest planet in proximity is Mars at 1.5 AU. We'll just assume that it still has enough energy to destroy Mars up that far.
3.01 AU is roughly 4.5029e+11 meters. This is our explosion radius.
GBE of Mars needs to be found first.
GBE= (3G(M^2))/5R
Mars has a radius of 3389.5 km or 3389500 m, and a mass of 6.39e+23 kg. Gravitational constant is 6.6704e-11 N⋅m^2⋅kg^−2
GBE of Mars= (3 * (6.6704e-11) * (6.39e+23^2) ) / (5 * 3389500)= 4.8213561e+30 J
Reverse-inverse square law for finding out power of explosion at epicenter for cosmic bodies time.
Energy of Explosion at Epicenter = 4 * U * (Er/Tr)^2, where U is GBE of the target body, Er is the Explosion Radius and Tr is the target's radius.
E = 4 * 4.8213561e+30 * (4.5029e+11/3389500)^2= 3.4036315e+41 J or 81.34874522 tenatons of TNT (Low 4-C, Small Star level+)
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The solar system doesn't end at the orbit of Neptune, it ends at the Oort cloud, with distances ranging from 2000 to 200000 AU so just destroying the 10% of the solar system would already cover Neptune's orbit. Although the point at which the Solar System ends is not precisely defined
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We don't use our baseline for Solar System level beyond Neptune.
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