- 11,539
- 10,954
The feat
The calc
From cloud calculation page
So basically feats like that divide by 12:
And feats like that divide by 4:
If I am correct, why does Mael's calculation use 12 and not 4? "Spreading them omnidirectionally around a center point" this is literally what Mael did in the feat
The calc
From cloud calculation page
One should keep in mind that not all clouds in a cloud movement feat necessarily move with the same speed. In such cases one has to calculate the kinetic energy with the different speeds of the different parts in mind. An example of this would be creating clouds and spreading them omnidirectionally around a center point. In that case the speed with which the clouds move may increase the further from the center they are. In the case of such an omnidirectional expansion one could use the formula "kinetic energy = 0.25 * cloud mass * (Speed of cloud movement)2" to account for the different speeds involved.
For pulling in clouds omnidirectional towards a center point, or dispersing them from a center point, the formula "kinetic energy = 1/12 * cloud mass * (Speed of cloud movement)2" can be used.
For pulling in clouds omnidirectional towards a center point, or dispersing them from a center point, the formula "kinetic energy = 1/12 * cloud mass * (Speed of cloud movement)2" can be used.
So basically feats like that divide by 12:
And feats like that divide by 4:
If I am correct, why does Mael's calculation use 12 and not 4? "Spreading them omnidirectionally around a center point" this is literally what Mael did in the feat