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That calc would be affected by the stuff discussed earlier in the thread, but it already includes a fine version just above it. Temperature change of 2977 degrees, density of 0.244 kg/m^3, and specific heat capacity of 919 j/kgk are all close enough to be fine.Would this calculation be affected?
In other words?It would be a slight lowball tho (like, 10-15% maybe) so you could recalc it if you're interested.
I mean does it reduces the calc by 10 to 15 percent?Which part of that would you want rephrased?
And as the hot air explodes outward, the hottest air goes outward too.So would the idea be that there's some amount of heat inside the explosion, that gets dispersed as it expands?
Rather than the entire sphere being one temperature at once, the inside is very hot, then that drifts to the outer front being somewhat hot with the inside being even less hot, etc.?
Real life explosions release energy in the form of heat and a shockwave, the reason the standard explosion formula needs to be cut in half is because the heat part of the explosion is assumed to be missing in fiction ( I think )Rather than the entire sphere being one temperature at once, the inside is very hot, then that drifts to the outer front being somewhat hot with the inside being even less hot, etc.?
That explains how we explain on the formula for the air blast non-nuclear detonation yield.We only cut it in half if it's non-nuclear.
My guess behind that is that nuclear bombs release half of their energy in ionizing radiation that normal bombs of the same size (destructive explosion radius-wise) don't have. And that it isn't about the pure heat component.
That is just my informed guess, though.
@KLOL506 @Jasonsith @Spinosaurus75DinosaurFan @DemonGodMitchAubin @ArmorchompyWhat are the conclusions here so far from DontTalkDT and our calc group members?
We were having a debate on density here?Not sure how I can help here possibly, since we're all waiting for DontTalk's opinion on which density is best to use and how to use it.
I think that was the situation? Because Bambu made mention of density of fire, but IDK.We were having a debate on density here?
Like, it of course depends, but generally I guess air density when at the temperature of the flame would be used to figure out mass and then do a regular heat change calc.
Hmmmmmm...Unless you are burning a chemical, in which case you could use chemical energy as well.
would this work?We were having a debate on density here?
Like, it of course depends, but generally I guess air density when at the temperature of the flame would be used to figure out mass and then do a regular heat change calc.
Unless you are burning a chemical, in which case you could use chemical energy as well.
Yeah... I mean, no vaporization. Air starts out as gas and all.I think that was the situation? Because Bambu made mention of density of fire, but IDK.
So basically, as per your reason, we'd use the density of air at the specific temperature it is burning in? Like say, air is x density at y temperature or something like that? And then it's just normal specific heat capacity and latent heat of vaporization?
I'm fairly sure the whole oxygen method on there is wrong.
Ah. Okay.Yeah... I mean, no vaporization. Air starts out as gas and all.