- 1,796
- 255
according to this
https://vsbattles.com/vsbattles/237785
discussion there were questions about the legitimacy of disneys hercules stats,
https://vsbattles.fandom.com/wiki/Hercules_(Disney)
the feats in question where him collapsing a mountain and tossing 4 titans into space with latter being the more impressive feat
kkapoios and me have revised the feat and calculated the final result (long calc incoming, scroll down for conclusions)
---
in the 1997 disney movies finale hercules grabs all the titans and throws them in outer space
we want to know the energy value to a) lift all the titans at once and b) throwing them out of the earths atmosphere
1. finding the size and mass of the titans
a) wind titan size
average single story house height is 3.6m
https://www.swiftestimator.com/main/seg/WebHelp/FieldHelp/buildingdata_averagestoryheight.htm
the story takes place in ancient greek - meaning less architectual progress and less need for opulent buildings for average people.
therefore the scaling for the houses height will be reduced to 3meter. leading us to the following scaling
http://i.imgur.com/1v59WaW.png
wind titan height: 180,75m
due to the massively differing portrayal of the titans proportion depending on the scene i will use the low end of his first on-screen width to scale it
http://i.imgur.com/Ztk9v70.png
wind titan width: 90,75m
a.1) volume of the tita
it is made clear the wind-titan is shaped like a cylinder
http://i.imgur.com/qayWAbr.png
which lets us utilize the width to find the volume
cylinder volume:
http://www.mathwarehouse.com/solid-...volume/picture-formula-volume-of-cylinder.png
V = 1169126.365914615m3
a.2) wind titan mass
on could argue the wind titan has little to no mass aside from the things he sucked in during his appearance, however it is made clear, while having wind-like properties he actually has a mass, as hercules was able to grab and throw him at his very bottom parts
http://i.imgur.com/GPwxr5G.png
we can find an answer to the problematic with the "air density and specific weight" formula which lets us utilize the temperature of the surroundings to find the airs density and specific weight
a.2.1) finding the temperature
the average temperature for the region of katerini (near the mount of olymp in real life) is 25 degree celsius.
http://www.holiday-weather.com/katerini/averages/
in that picture we see the lava/magma titan is directly before him, leaving a trail of magma/lava. magma and lava radiates heat
http://i.imgur.com/qayWAbr.png
assuming the standard lava heat of 1.300 degree celsius the heat radiation is 50 degree celsius
hd=tan2¤Ç5Ôïà1030.8Ôïà5.6Ôïà10ÔêÆ813004(0.2)
which adds up to the 25 degree celsius we have from the average weather
a.3) adding it up
taking a look at this chart we find the following values for air density and specific weight with a 75degree temperature
http://www.engineeringtoolbox.com/air-density-specific-weight-d_600.html
~ 1.928 density and therefore almost double as high as the regular density from the air surrounding us in the every day life. good, that we implemented that step
now we solve for the mass
https://d2gne97vdumgn3.cloudfront.net/api/file/IJFoEQ0QWehsozW7rKRl
Mass = Volume × Density (-> result already converted to KG by me to avoid unneccesary steps)
1169126.365914615 x 1.928 = 2.254,0756
the wind titans has a mass off 2.254,0756 kilograms
b) frost titan size
the average horse height for a light riding horse is 1.50m
https://en.wikipedia.org/wiki/Horse
which leads us to following scaling
http://i.imgur.com/muqXxoE.png
frost titan height: 55.85m
finding the width will prove difficult since he more or less consists of different seperate parts instead of one big piece of mass, therefore we will use the lazy approach and just scale the low middle part, to put it in perspective with the rest of the tita
http://imgur.com/s7QVo3K
frost titan width: 9.26m
finding the depth on the other hand is rather easy. ice consists of a very high density so its not a problem that his depth is not as great as is overall structure
http://imgur.com/3je890U
frost titan depth: 1.05m
b.1) frost titan volume
having the values we solve them to find the volume
http://imgur.com/MWUQtxi
http://www.calculator.net/volume-ca...eightunit=meter&rectcal=Calculate#rectangular
Volume = 1.05×9.26×55.85 = 543.02955m3
b.2) frost titan mass
we multiply the volume with density of ice which is 916.8 kg/m3
http://hypertextbook.com/facts/2000/AlexDallas.shtml
again:
https://d2gne97vdumgn3.cloudfront.net/api/file/IJFoEQ0QWehsozW7rKRl
Mass = Volume × Density (-> result already converted to KG by me to avoid unneccesary steps)
Mass = 543.02955 x 916.8 = 497849.49144
the frost titan has a mass off 497849.49144 kilograms
c) lava titan size
easy to scale due to its "blobby" form we find height, width and depth on the get go
http://imgur.com/2ocmZ10
lavatitan height: 39.58m
lavatitan width: 15.18m
lavatitan depth: 13.01m
c.1) lava titan volume
we utilize the volume of an vertical oval. since we know the whole body is filled with lava ( prove here:http://imgur.com/8EQ5JKX ), we find an accurate volume
http://www.calculatorsoup.com/calculators/construction/tank.php
volume: 71733,651m3
c.2) lava titan mass
"The lavas are completely liquid at 1250 degrees Celcius"
http://www.madsci.org/posts/archives/1999-11/943417499.Es.r.html
which is the case for our lava titan. calculated at 2.17 g each cubic centimer (low end) we can multiply the density of liquid lava with the prior found volume to get the mass
again:
https://d2gne97vdumgn3.cloudfront.net/api/file/IJFoEQ0QWehsozW7rKRl
Mass = Volume × Density (-> result already converted to KG by me to avoid unneccesary steps)
Mass = 71733,651 x 2170 = 155662022.67
the lava titan has a mass off 15226036.6003676 kilograms
d) stone titan size
http://imgur.com/2Iu4w0r
stone titan height: 59.64m
stome titan width: 29.82m
for the depth we use a different picture
http://imgur.com/49blDQk
stone titan depth: 19.96m
d.1) stone titan volume
for the volume we use a rectangle
http://imgur.com/lYjGHJi
we know the part between his legs is without mass, but at the same time we do not include his arms, which evens that more than enough times out agai
Volume = 1.05×9.26×55.85 = 543.02955m3
http://www.calculator.net/volume-ca...eightunit=meter&rectcal=Calculate#rectangular
d.2) stone titan mass
concrete density 2.400 kg/m3
http://www.rfcafe.com/references/general/density-building-materials.htm
and for the last time:
https://d2gne97vdumgn3.cloudfront.net/api/file/IJFoEQ0QWehsozW7rKRl
Mass = Volume × Density (-> result already converted to KG by me to avoid unneccesary steps)
Mass = 543.02955 x 2400 = 1303270.92
the lava titan has a mass off 1303270.92 kilograms
2. adding the masses
mass wind titan: 2254.0756
mass frost titan: 497849.49144
mass lava titan: 155662022.67
mass stone titan: 1303270.92
total mass: 157.465.397,15704 kilograms lifted
In order to lunch the titans into space Hercules would have to throw them at escape velocity
Mass = 157.465.397 kg
V = 11200 m/s
KE = 1/2 m *v^2
KE = 9.876e15 Joules ( 2.36 Megatons ) Small City level
---
conclusion: the mountain level AP and durability shall be changed from Mountain level to Small City level
https://vsbattles.com/vsbattles/237785
discussion there were questions about the legitimacy of disneys hercules stats,
https://vsbattles.fandom.com/wiki/Hercules_(Disney)
the feats in question where him collapsing a mountain and tossing 4 titans into space with latter being the more impressive feat
kkapoios and me have revised the feat and calculated the final result (long calc incoming, scroll down for conclusions)
---
in the 1997 disney movies finale hercules grabs all the titans and throws them in outer space
we want to know the energy value to a) lift all the titans at once and b) throwing them out of the earths atmosphere
1. finding the size and mass of the titans
a) wind titan size
average single story house height is 3.6m
https://www.swiftestimator.com/main/seg/WebHelp/FieldHelp/buildingdata_averagestoryheight.htm
the story takes place in ancient greek - meaning less architectual progress and less need for opulent buildings for average people.
therefore the scaling for the houses height will be reduced to 3meter. leading us to the following scaling
http://i.imgur.com/1v59WaW.png
wind titan height: 180,75m
due to the massively differing portrayal of the titans proportion depending on the scene i will use the low end of his first on-screen width to scale it
http://i.imgur.com/Ztk9v70.png
wind titan width: 90,75m
a.1) volume of the tita
it is made clear the wind-titan is shaped like a cylinder
http://i.imgur.com/qayWAbr.png
which lets us utilize the width to find the volume
cylinder volume:
http://www.mathwarehouse.com/solid-...volume/picture-formula-volume-of-cylinder.png
V = 1169126.365914615m3
a.2) wind titan mass
on could argue the wind titan has little to no mass aside from the things he sucked in during his appearance, however it is made clear, while having wind-like properties he actually has a mass, as hercules was able to grab and throw him at his very bottom parts
http://i.imgur.com/GPwxr5G.png
we can find an answer to the problematic with the "air density and specific weight" formula which lets us utilize the temperature of the surroundings to find the airs density and specific weight
a.2.1) finding the temperature
the average temperature for the region of katerini (near the mount of olymp in real life) is 25 degree celsius.
http://www.holiday-weather.com/katerini/averages/
in that picture we see the lava/magma titan is directly before him, leaving a trail of magma/lava. magma and lava radiates heat
http://i.imgur.com/qayWAbr.png
assuming the standard lava heat of 1.300 degree celsius the heat radiation is 50 degree celsius
hd=tan2¤Ç5Ôïà1030.8Ôïà5.6Ôïà10ÔêÆ813004(0.2)
which adds up to the 25 degree celsius we have from the average weather
a.3) adding it up
taking a look at this chart we find the following values for air density and specific weight with a 75degree temperature
http://www.engineeringtoolbox.com/air-density-specific-weight-d_600.html
~ 1.928 density and therefore almost double as high as the regular density from the air surrounding us in the every day life. good, that we implemented that step
now we solve for the mass
https://d2gne97vdumgn3.cloudfront.net/api/file/IJFoEQ0QWehsozW7rKRl
Mass = Volume × Density (-> result already converted to KG by me to avoid unneccesary steps)
1169126.365914615 x 1.928 = 2.254,0756
the wind titans has a mass off 2.254,0756 kilograms
b) frost titan size
the average horse height for a light riding horse is 1.50m
https://en.wikipedia.org/wiki/Horse
which leads us to following scaling
http://i.imgur.com/muqXxoE.png
frost titan height: 55.85m
finding the width will prove difficult since he more or less consists of different seperate parts instead of one big piece of mass, therefore we will use the lazy approach and just scale the low middle part, to put it in perspective with the rest of the tita
http://imgur.com/s7QVo3K
frost titan width: 9.26m
finding the depth on the other hand is rather easy. ice consists of a very high density so its not a problem that his depth is not as great as is overall structure
http://imgur.com/3je890U
frost titan depth: 1.05m
b.1) frost titan volume
having the values we solve them to find the volume
http://imgur.com/MWUQtxi
http://www.calculator.net/volume-ca...eightunit=meter&rectcal=Calculate#rectangular
Volume = 1.05×9.26×55.85 = 543.02955m3
b.2) frost titan mass
we multiply the volume with density of ice which is 916.8 kg/m3
http://hypertextbook.com/facts/2000/AlexDallas.shtml
again:
https://d2gne97vdumgn3.cloudfront.net/api/file/IJFoEQ0QWehsozW7rKRl
Mass = Volume × Density (-> result already converted to KG by me to avoid unneccesary steps)
Mass = 543.02955 x 916.8 = 497849.49144
the frost titan has a mass off 497849.49144 kilograms
c) lava titan size
easy to scale due to its "blobby" form we find height, width and depth on the get go
http://imgur.com/2ocmZ10
lavatitan height: 39.58m
lavatitan width: 15.18m
lavatitan depth: 13.01m
c.1) lava titan volume
we utilize the volume of an vertical oval. since we know the whole body is filled with lava ( prove here:http://imgur.com/8EQ5JKX ), we find an accurate volume
http://www.calculatorsoup.com/calculators/construction/tank.php
volume: 71733,651m3
c.2) lava titan mass
"The lavas are completely liquid at 1250 degrees Celcius"
http://www.madsci.org/posts/archives/1999-11/943417499.Es.r.html
which is the case for our lava titan. calculated at 2.17 g each cubic centimer (low end) we can multiply the density of liquid lava with the prior found volume to get the mass
again:
https://d2gne97vdumgn3.cloudfront.net/api/file/IJFoEQ0QWehsozW7rKRl
Mass = Volume × Density (-> result already converted to KG by me to avoid unneccesary steps)
Mass = 71733,651 x 2170 = 155662022.67
the lava titan has a mass off 15226036.6003676 kilograms
d) stone titan size
http://imgur.com/2Iu4w0r
stone titan height: 59.64m
stome titan width: 29.82m
for the depth we use a different picture
http://imgur.com/49blDQk
stone titan depth: 19.96m
d.1) stone titan volume
for the volume we use a rectangle
http://imgur.com/lYjGHJi
we know the part between his legs is without mass, but at the same time we do not include his arms, which evens that more than enough times out agai
Volume = 1.05×9.26×55.85 = 543.02955m3
http://www.calculator.net/volume-ca...eightunit=meter&rectcal=Calculate#rectangular
d.2) stone titan mass
concrete density 2.400 kg/m3
http://www.rfcafe.com/references/general/density-building-materials.htm
and for the last time:
https://d2gne97vdumgn3.cloudfront.net/api/file/IJFoEQ0QWehsozW7rKRl
Mass = Volume × Density (-> result already converted to KG by me to avoid unneccesary steps)
Mass = 543.02955 x 2400 = 1303270.92
the lava titan has a mass off 1303270.92 kilograms
2. adding the masses
mass wind titan: 2254.0756
mass frost titan: 497849.49144
mass lava titan: 155662022.67
mass stone titan: 1303270.92
total mass: 157.465.397,15704 kilograms lifted
In order to lunch the titans into space Hercules would have to throw them at escape velocity
Mass = 157.465.397 kg
V = 11200 m/s
KE = 1/2 m *v^2
KE = 9.876e15 Joules ( 2.36 Megatons ) Small City level
---
conclusion: the mountain level AP and durability shall be changed from Mountain level to Small City level
