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Calculation Requests II

There’s a moment in one of my stories where a character absorbs all the stars in the Alpha Centauri system and then after that, she wields their power.

I know that’s clearly 4-C, but how high is it exactly?
 
What speed would it take to blitz ”well over half a dozen” mooks in the time it takes for electricity to travel from the shoulder to the brain?
 
How many volts would it take for an electric power to make it seem like the day for “several minutes?” They flew above a forest a few hours walk from a relatively big city in Japan and some people on the outskirts thought it was dawn while people in a nearby log cabin genuinely thought they were the sun at first, unable to even look at them.
 
Wdinatx said:
What tier would it be to punch someone through two kilometers of rock?
Click to expand...

Now, if we consider that the sledgehammer power required to break a 12 cm wide brick wall is 63160N, if we multiply this number 16.666 times, it should be 1.052.662.660N. Thus, we find the power required to break a 2 km thick brick wall. Although the density of the brick and stone varies, I assume that the density of both is equal.
I am a beginner in this business, so re calculation may needed.
For source
This
And this
 
LeoEpicGamer8910 said:
Bump
Click to expand...
That'll be something very hard to calculate because the background is completely white thus, we aren't sure what we can refer to pixel scale. And it didn't show what caused that explosion.
 
GarrixianXD said:
That'll be something very hard to calculate because the background is completely white thus, we aren't sure what we can refer to pixel scale. And it didn't show what caused that explosion.
Click to expand...
It's fine. Even if it was calced, it'd probably be a support feat thanks to Jeramiah Calhoun now being straight-up 9-A, and I doubt it'd be higher than that.
 
MassiveMeddlers said:
Now, if we consider that the sledgehammer power required to break a 12 cm wide brick wall is 63160N, if we multiply this number 16.666 times, it should be 1.052.662.660N. Thus, we find the power required to break a 2 km thick brick wall. Although the density of the brick and stone varies, I assume that the density of both is equal.
I am a beginner in this business, so re calculation may needed.
For source
This
And this
Click to expand...
For a calc requiring destruction, such as destroying 2 km of rock, we would used Joules of energy, not newtons of force. I can probably try to calculate the feat once I get home
 
ThePrimalHunter said:
For a calc requiring destruction, such as destroying 2 km of rock, we would used Joules of energy, not newtons of force. I can probably try to calculate the feat once I get home
Click to expand...
The newton can first be converted to newton meters and then to joules. Because a sledgehammer technically acts more like a lever with a handle between about 50 centimeters and 1 meter to a force rather than a punch. if we take it as a .75 meter long sledgehammer, the force will be 789496995 n/m and the conversion to joules is 1:1.
If true, that's 7.89 x10^8. 9-A
It's still questionable, but I thought I'd do it : P
 
Wdinatx said:
What tier would it be to punch someone through two kilometers of rock?
Click to expand...
So I'm going to assume that the size of the hole is that of a human, but that they were just punched 2km into it

Surface area of a human = 9,500 cm^2

2km = 200,000 cm

9,500 * 200,000 = 1,900,000,000 cm^3

Fragmentation: 1,900,000,000 * 8 J/cc = 15,200,000,000 Joules, or 3.633 Tons of TnT (Large Building level)
Violent Fragmentation: 1,900,000,000 * 69 J/cc = 131,100,000,000 Joules, or 31.33 Tons of TnT (City Block level)
Pulverization = 1,900,000,000 * 214 J/cc = 406,600,000,000 Joules, or 97.18 Tons of TnT (City Block level+)
 
GarrixianXD said:
Really depends on how fast they've done it honestly.
Click to expand...
If it was done in 1 punch, well
ThePrimalHunter said:
So I'm going to assume that the size of the hole is that of a human, but that they were just punched 2km into it

Surface area of a human = 9,500 cm^2

2km = 200,000 cm

9,500 * 200,000 = 1,900,000,000 cm^3

Fragmentation: 1,900,000,000 * 8 J/cc = 15,200,000,000 Joules, or 3.633 Tons of TnT (Large Building level)
Violent Fragmentation: 1,900,000,000 * 69 J/cc = 131,100,000,000 Joules, or 31.33 Tons of TnT (City Block level)
Pulverization = 1,900,000,000 * 214 J/cc = 406,600,000,000 Joules, or 97.18 Tons of TnT (City Block level+)
Click to expand...
 
ThePrimalHunter said:
So I'm going to assume that the size of the hole is that of a human, but that they were just punched 2km into it

Surface area of a human = 9,500 cm^2

2km = 200,000 cm

9,500 * 200,000 = 1,900,000,000 cm^3

Fragmentation: 1,900,000,000 * 8 J/cc = 15,200,000,000 Joules, or 3.633 Tons of TnT (Large Building level)
Violent Fragmentation: 1,900,000,000 * 69 J/cc = 131,100,000,000 Joules, or 31.33 Tons of TnT (City Block level)
Pulverization = 1,900,000,000 * 214 J/cc = 406,600,000,000 Joules, or 97.18 Tons of TnT (City Block level+)
Click to expand...
Yeah, that works as well.
 
I have a Calc I just need evaluated

Importance/Priority: It’d be a tier, AP, and durability upgrade for both Sora and Pit
Name of the Verse/Character: Sora (Death Battle!)
Brief Feat Description: Pit knocks Sora up into the sky and then charges through three pillars with him
 
MintyBoi1 said:
I have a Calc I just need evaluated

Importance/Priority: It’d be a tier, AP, and durability upgrade for both Sora and Pit
Name of the Verse/Character: Sora (Death Battle!)
Brief Feat Description: Pit knocks Sora up into the sky and then charges through three pillars with him
Click to expand...
I replied on the blog, but you should know that this isn't the place to ask for an evaluation. This is the place to request calcs, FC/OC doesn't really have a thread to "evaluate calcs" and that's not even necessary at all (aside from minor corrections i guess?).
 
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