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Yhwach based power after after he elevates the Vanderich .
"There is a way to determine the gpe:
See, 9.8 is the general number we use for everything close to the surface of the earth because it's convenient. This is the actual equation for gravititional attraction. G is a constant, and plugging in you're mass for mass 1 we get this far.
F=Gm1m2/r^2 F=6.67*(10^-11)*5.402*(10^13)*m2/r^2 F=36.03134*100*m2/r^2 F=3603.134*m2/r^2
we'll have to assume mass 2 is equal to the earth which seems fair enough because the surface gravity is the same as it is in the world of the living. Also assuming part of r is the radius of the earth because If gravity and mass were the same as earth this'd have to be.
F=3603.134*5.972*(10^24)/(5968589760+6378100)^2 F=21517916248000000000000000000/35700240928032979600 F=602738684.35166326167392849607985N
Work done is force over distance, basically newtons are the same thing as joules per metre (that's why the regular gpe equation is E=g*m*h, g is newtons per kilo so it's basically E=(F/m)*m*h, the ms cancel out and it becomes E=f*h -> F=E/h, h being in metres).
E=F*d E=602738684.35166326167392849607985*35624063723176857600 E=21472001299767433892051645112.562 E=513.193Exatons
Seriously with a reasonable distance we'd get an accurate number... the distance I used was your distance plus the radius of the earth (the latter being mostly negligable), the massive number in there is that sqaured because the equation is F=Gm1m2/r^2.
Moon level Yhwach, seems legit.
"There is a way to determine the gpe:
See, 9.8 is the general number we use for everything close to the surface of the earth because it's convenient. This is the actual equation for gravititional attraction. G is a constant, and plugging in you're mass for mass 1 we get this far.
F=Gm1m2/r^2 F=6.67*(10^-11)*5.402*(10^13)*m2/r^2 F=36.03134*100*m2/r^2 F=3603.134*m2/r^2
we'll have to assume mass 2 is equal to the earth which seems fair enough because the surface gravity is the same as it is in the world of the living. Also assuming part of r is the radius of the earth because If gravity and mass were the same as earth this'd have to be.
F=3603.134*5.972*(10^24)/(5968589760+6378100)^2 F=21517916248000000000000000000/35700240928032979600 F=602738684.35166326167392849607985N
Work done is force over distance, basically newtons are the same thing as joules per metre (that's why the regular gpe equation is E=g*m*h, g is newtons per kilo so it's basically E=(F/m)*m*h, the ms cancel out and it becomes E=f*h -> F=E/h, h being in metres).
E=F*d E=602738684.35166326167392849607985*35624063723176857600 E=21472001299767433892051645112.562 E=513.193Exatons
Seriously with a reasonable distance we'd get an accurate number... the distance I used was your distance plus the radius of the earth (the latter being mostly negligable), the massive number in there is that sqaured because the equation is F=Gm1m2/r^2.
Moon level Yhwach, seems legit.
