What Calc is this? (Kaguya's Truth Seeking Ball OBD)

[CNBA3]

First I would like to say that it is so annoying that it keeps crashing every time I try to open it.

Now I wish to know what calc is this used for Kaguya's Truth seeking ball, and what are the values needed to find everything.

And if possible, copy and past what it says on the blog itself.

http://www.narutoforums.com/blog.php?b=24739

 

[Mindovin]

Did you try to open on phone or pc? Sometimes it crashes when I try to open blogs on my phone.

Introductio
This is the final calculation of the Naruto revisions (or so I hope). The be-all-end-all, if you will. I'm going to cover Kaguya's ETSB once again.

We know and have accepted the fact that Kaguya's planets contain moons, so I'm just going straight to the calc. Since Kaguya was going to destroy her entire dimension with the ETSB, we're forced to use the inverse square law to calculate the feat.

Kaguya's moons are as far as away as the real one going by the movie's portrayal, so it's justified.

The Calc

• Radius of the moon = 1,737.5 kilometers
• Frontal area of the moon = pi*(1737500)^2 = 9.4841737e+12 m^2
• GBE of the Moon = 1.2x10^29 joules

The distance between the Moon and the Earth is 384400km.

• Area of the explosion = 4*pi*(384400000)^2 = 1.8568491e+18 m^2
• E = 1.8568491e+18 / 9.4841737e+12 * 1.2e+29
• E = 2.3494075e+34 joules, or 5.61521869025 yottatons of TNT (Large Planet level)

Results

Throw an Upgrade to End it All: 5.61521869025 yottatons of TNT (Large Planet level)

 

[CNBA3]

Did you try to open on phone or pc? Sometimes it crashes when I try to open blogs on my phone.

Introductio

This is the final calculation of the Naruto revisions (or so I hope). The be-all-end-all, if you will. I'm going to cover Kaguya's ETSB once again.

We know and have accepted the fact that Kaguya's planets contain moons, so I'm just going straight to the calc. Since Kaguya was going to destroy her entire dimension with the ETSB, we're forced to use the inverse square law to calculate the feat.

Kaguya's moons are as far as away as the real one going by the movie's portrayal, so it's justified.

The Calc

• Radius of the moon = 1,737.5 kilometers
• Frontal area of the moon = pi*(1737500)^2 = 9.4841737e+12 m^2
• GBE of the Moon = 1.2x10^29 joules

The distance between the Moon and the Earth is 384400km.

• Area of the explosion = 4*pi*(384400000)^2 = 1.8568491e+18 m^2
• E = 1.8568491e+18 / 9.4841737e+12 * 1.2e+29
• E = 2.3494075e+34 joules, or 5.61521869025 yottatons of TNT (Large Planet level)

Results

Throw an Upgrade to End it All: 5.61521869025 yottatons of TNT (Large Planet level)
Sorry, I meant from Outskirts Battledome calc

http://www.narutoforums.com/blog.php?b=24739

 

[Mindovin]

Try this.

 

[CNBA3]

Try this.

Cool thanks, so, all I need to do to find right one is go to the archive pages?

 

[Mindovin]

https://web.archive.org/

 

[CNBA3]

Thank you

 

[Mindovin]

No problem