We usually go off area for calcs, tho...
Now if you REALLY wanna go out of your way and destroy the goshdang planetoid as a whole, well, I did this:
http://prntscr.com/uu34me
I measured Jeju Island as the reference point for the planetoid, which would be 78.36 km in length. It was 79.8 pixels long in the screencap. I then went out of my way to use the Rectangular Select Tool to measure out the planetoid as the thing was a bit too awkward-looking to measure otherwise and got this:
http://prntscr.com/uu3770
The thing's dimensions are 848x823 px. That would equate to cross-sections that are the following:
Length: 848/79.8*78.36=832.6977 km
Width: 823/79.8*78.36=808.1489 km
Now l got this for the area after measuring all that out. Bear in mind that the cross-sections work the same as the diameter in the circle, so I had to divide each by 2:
(832.6977/2)*(808.1489/2)*π=528528.7798 km²
Add in 35 km for continental crust's thickness (bearing in mind that the thing doesn't allow us to accurately measure thickness otherwise) (
https://www.cs.mcgill.ca/~rwest/wikispeedia/wpcd/wp/c/Continental_crust.htm ) and you get a volume of about 18498507.293014 km³
Only 219155 km² of that is actually the continent itself, so out of all that, we would know that 7670425 km³, or 7.670425*10^15 m³ of that volume is continental. That would put Korea itself's mass at, assuming 2600 to 2800 kg/m³ for granite (a main constituent of crust), we'd get a mass of 1.9943105*10^19 kg to 2.147719*10^19 kg
The rest is covered by water. Seawater has a density of 1024 kg/m³ at 20 degrees celsius (
http://www.ric.edu/faculty/PSCI103/Seawater/Seawater_notes.htm ), so there's that. Now, I had to really go out of my way for this one. I split both parts of the ocean into two. I had to make a circle encompassing the thing beforehand (making sure I got the radius right) and, well...:
http://prntscr.com/uu3z2l
To the left, the deepest part of the ocean I can get is 367 feet near dead-center:
http://prntscr.com/uu42c0
On the right? 9812 feet in this marked section:
http://prntscr.com/uu41ge
This in mind, this is how much of the planetoid's area is water: 528528.7798-219155=309373.7798 km²
Divide that by 2 and you got 154686.8899 km² for each side. Here are the median values of depth for each side.:
(367/2)*12*2.54/100=55.9308 m
(9812/2)*12*2.54/100=1495.3488 m
Plugging these in, we got the following.
Left: 154686.8899*.0559308=8651.7615 km³
Right: 154686.8899*1.4953488=231310.8552 km³
Total: 8651.7615+231310.8552=239962.6167 km³=2.3996*10^14 m³
Using this, we'll take our figure of 1024 kg/m³ for seawater's density from before and her a mass of 2.4572*10^17 kg.
This would leave just another 10588119.676324 km³ of crust left unaccounted for. This unaccounted-for crust would have a mass of 2.7529 to 2.9657*10^19 kg.
Adding that and Korea's crust together, I got a mass value ranging from 4.7472 to 5.1124*10^19 kg. This would equate to... (7670425+10588119.676324)=18258544.68 km³, or 1.8258*10^22 cm³ of rock. Assuming 8 j/cm for merely fragmenting that thing, you get a value of 1.4607*10^23 joules, or
34.9112 teratons of TNT. Just a smidge higher... at
6-B, aka
Country Level. Yep.
So you either get Baseline Low 6-B for destroying the land area of that thing, or solid 6-B for the entire bulk of the thing.