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This isn't meant to be a revision thread or anything. This is only meant to peer review and improve the measurement for Goku's lifting strength before the 21st Budokai. This should be more accurate since we can ignore the scaling that happens much later in the series.
I did some googling, and I found the right image to calculate the rock as a cube with a debatable scale of reference for 1 meter.
I also found this calculation for the rock as a cylinder and semicircle with another debatable scale of reference.
While I would like to make a similar calculation, I decided to try the prism with a more accurate scale of reference using Roshi's canon height and the distance from the top of his head to the bottom of his ear.
Density of Rock: 2.4 - 3.3 g/cm^3 = 2400000 g/m^3 = 2400 kg/m^3 = 2.4 Metric Tons/m^3
Since Goku pushed the rock instead of lifting it, we need to calculate the force needed to overcome the static friction between the rock and the ground. Concrete on
http://usacetechnicalletters.tpub.com/ETL-1110-3-446/ETL-1110-3-4460006.htm
Coefficient of friction of concrete on soil: .3
Rock Weight = 2.4*(.29/35.4*536)*(.29/35.4*664)^2 = 311.814565245 Metric Tons of Force
Initial Horizontal Force = 311.814565245 * .3 = 93.5443695734 Metric Tons of Force
Looking at his face, Goku can dead-push? 93.5443695734 Metric Tons as a kid.
Any questions, comments, or concerns?
I did some googling, and I found the right image to calculate the rock as a cube with a debatable scale of reference for 1 meter.
I also found this calculation for the rock as a cylinder and semicircle with another debatable scale of reference.
While I would like to make a similar calculation, I decided to try the prism with a more accurate scale of reference using Roshi's canon height and the distance from the top of his head to the bottom of his ear.
Density of Rock: 2.4 - 3.3 g/cm^3 = 2400000 g/m^3 = 2400 kg/m^3 = 2.4 Metric Tons/m^3
Since Goku pushed the rock instead of lifting it, we need to calculate the force needed to overcome the static friction between the rock and the ground. Concrete on
http://usacetechnicalletters.tpub.com/ETL-1110-3-446/ETL-1110-3-4460006.htm
Coefficient of friction of concrete on soil: .3
Rock Weight = 2.4*(.29/35.4*536)*(.29/35.4*664)^2 = 311.814565245 Metric Tons of Force
Initial Horizontal Force = 311.814565245 * .3 = 93.5443695734 Metric Tons of Force
Looking at his face, Goku can dead-push? 93.5443695734 Metric Tons as a kid.
Any questions, comments, or concerns?
