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Question about 2-A

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If you destroy a portion of a 2-A multiverse. Does it make you 2-A? So yes, is it so far as even destroying 1% is enough for 2-A, because you are still destroying a 1% portion of infinite and infinite divided by 100 is infinite. So...
 
thechinically destroying a part of infinite multiverse would be still 2-A (in certain case 2-B, likely 2-A but ok)
however destroying tot universes of a infinite multiverse, then it's 2-C or 2-B (that's normal ig)
 
It is not clear what you are asking about destroying part of an infinite number of universes.

What are you referring to when you say "portion" here? The percentage of something and a "portion" are something else.

For example, suppose you have 100 balls in a box. In this case, destroying 50 balls in the box means destroying 50% of them.
From this perspective, "percentage" and "portion" seem to mean the same thing.

But the truth of the matter is not quite so.
If we're talking about eternities, we may be a little wrong about what we know.


Let's go back to our box example. Imagine an infinitely large box.
Let it have an infinite number of balls in it. If we destroy 10 of these infinite number of cannons, we destroy "a portion".

The same is true in universes. Let's imagine a reality where there are an infinite number of universes.
When we destroy only 5 of the infinite number of universes in that reality, we are destroying a "portion".
But that doesn't give us the 2-A tier, it just gives us 2-C.

I mean, what you mean here depends on how the word "portion" is used in context.
 
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