Is there an method to calced LS based around this?
So, there is a method to calculate Lifting Strength (LS) from this feat, though it’s inherently approximate, assumption-heavy (context matters, a lot in fact. we lack field strength, distances, accelerations, or exact setup)
It relies on equating the magnetic pulling force (which successfully drags Character B and other heavy metallic objects) to the counter-force Character A must exert to resist being pulled. Since A is also metallic and affected by the same field yet doesn’t budge, A’s physical strength (or anchoring ability) is at least equal in magnitude to the force acting on comparable objects.
Magnetic force on a ferromagnetic object (like metal characters/objects) isn’t simply “pulls X kg.” It depends on:
The magnetic field strength B (in teslas) and its gradient ∇B (how sharply it changes with distance).
The object’s volume V, magnetic susceptibility χ (how easily it magnetizes), and permeability μ.
Distance from the source (force drops off rapidly, often ~1/r⁴ or steeper for dipoles).
A simplified formula for the force on a magnetizable object in a non-uniform field is roughly: F≈Vχμ0 (B⋅∇)B
(where μ0 is the permeability of free space). But in practice, for power-scaling, we don’t have these values—so we use the observable effect on Character B as a proxy. The field exerts enough force on B (mass mB=380.7 m_B = 380.7 mB=380.7 kg) to overcome whatever is resisting its motion (gravity if vertical/lifting-like, or friction + inertia if horizontal drag).
The key assumption: The field’s pull is strong enough to move B and other heavy objects toward the source. Character A resists the same field, so A generates an equal-or-greater opposing force through physical means (muscles, structural integrity, grip on the ground, etc.).
Quantify the minimal force on B: Use F≥mB×g (where g≈9.81 m/s²) as the low-end. This assumes the pull must at least counteract B’s weight (as if lifting or pulling vertically/upward against gravity). This is the most common baseline because the description (“pull all other metallic objects toward it”) often implies overcoming ground contact or free movement. Calculation:
Fmin=380.7 kg×9.81 ms2=3734.667 N This force is exactly equivalent to the upward force needed to lift 380.7 kg against Earth gravity (since 1 kgf ≈ 9.81 N, it’s ~380.7 kgf)
Don't quote me on any of this... it's midnight and I'm probably missing a lot of things.