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Inverse Square Law Explosion

Mr_Sugabz

He/Him
232
56
What is CA when i using Inverse Square Law?
is CA the cross-sectional area of the object affected by the blast, which in this case is the character affected by the blast?
If so, is the formula for calculating CA as stated in wikipedia:
{BSA}=0.007184\times W^{0.425}\times H^{0.725}

???
 
CA is the Cross-Sectional Area of a human being, usually 40-50% that of total human body surface area.

We usually use 0.68 m^2 for the average person, but use it only if you have no concrete height-and-weight listings for the person.
 
What is CA when i using Inverse Square Law?
is CA the cross-sectional area of the object affected by the blast, which in this case is the character affected by the blast?
If so, is the formula for calculating CA as stated in wikipedia:
{BSA}=0.007184\times W^{0.425}\times H^{0.725}

???
((0.007184 * (weight in kilograms)^0.425 * ((height in meters) * 100)^0.725) * 0.45)


With this formula you can calculate the cross-sectional area of a character, if you know their weight and height.
 
CA is the Cross-Sectional Area of a human being, usually 40-50% that of total human body surface area.

We usually use 0.68 m^2 for the average person, but use it only if you have no concrete height-and-weight listings for the person.
does it mean, the total after I calculate the Surface Area using the above formula, I should divide the result by 2. Right?
 
((0.007184 * (weight in kilograms)^0.425 * ((height in meters) * 100)^0.725) * 0.45)


With this formula you can calculate the cross-sectional area of a character, if you know their weight and height.

Is this different from the top one?
 
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