how to find Joule Meter from Acceleration or Speed?

[CNBA3]

So in this thread I am trying to get a best estimate for how to find the joules from the joule/meters = netwons, It is with a person who is accelerating towards lightspeed, starting at 1/3rd Earth's G-Force. I got the final velocity for free falling with height. I did a ratio conversion for 99.999% SoL, so now wish to know what I should use for distance (meters) to get joules. should I just stick to 1 meter?

1/3 Earth's G-force = 3.27 m/s^2

initial v = 0.01 m/s

height = 7015.38 meters

time = 65.5 sec

final v = 214.2

----

4576617.81 m/s^2 = 466685.14 g-f = 299789460 m/s = 99.999% SoL

Newtons from Mass of person = 767303173.0418401 N

P.S., is this an accurate way to get G-Force tolerance measurement?

 

[Imaginym]

Bumping for interest.

 

[RoggerReggor]

I believe you found the force exerted by the character, and want to find the work done by the body in joules?

Well, it is simple, you can simply use the formula below:

Work Done = (Force)(Displacement(cosθ)

where Force is the force exerted, Displacement is the straight distance between the initial and final positions of the character, and θ is the angle between the direction of force and the direction of displacement, which I believe will be zero in this case.

So, assuming that the character accelerates over the entire distance, which he does assuming from the OP.

Work Done = 767303173.0418401*7015.38 = 5.3829233e+12 Joules or 1286.549545889101 tons of TNT

I might be wrong though, you should tag a CGM for their opinion on the thread as well.

 

[CNBA3]

I believe you found the force exerted by the character, and want to find the work done by the body in joules?

Well, it is simple, you can simply use the formula below:

where Force is the force exerted, Displacement is the straight distance between the initial and final positions of the character, and θ is the angle between the direction of force and the direction of displacement, which I believe will be zero in this case.

So, assuming that the character accelerates over the entire distance, which he does assuming from the OP.

Work Done = 767303173.0418401*7015.38 = 5.3829233e+12 Joules or 1286.549545889101 tons of TNT

I might be wrong though, you should tag a CGM for their opinion on the thread as well.

Much appreciated thank you.

 

[Vzearr]

Late ah reply.