How much energy you need to split the sun/a planet as big as the sun?

[Lord_JJJ]

^

 

[DxGenesis]

Split how? With a punch? By cutting it in half with like a sword? Does it leave a visible gap? More context is needed to answer that.

 

[Lord_JJJ]

With a punch and there is a visibale gap, sorry for not giving more context.

 

[Robot972]

Would it be possible to provide an image or is it text?

 

[DxGenesis]

If it's with a punch and it's something like the sun then it can't be calculated because it makes no physical sense. However if it's a solid surface it should be not too hard to calc by treating it as an earthquake.
Still, it would be better if you could give more context.

 

[Lord_JJJ]

Sorry, I don't really has a reference, I just question that out of curiosity

 

[DxGenesis]

If you treat it as an Earthquake happening on a planet similar to Earth but Sun-sized, and lowball by treating it as a planet-wide Mercalli Class XII (Richter 9), you get 5-A.

Richter Magnitude of Earthquake = (Magnitude at distance) + 6.399 + 1.66×log((distance from epicenter in KM/110)×((2×π)/360))
Circumference of the Sun / 2 = 2.19e6 km
Magnitude at a distance = 9
9 + 6.399 + 1.66×log((2.19e6/110)×((2×π)/360)) = 19.6169418
Richter Magnitude = 19.6169418
Energy = 10^(1.5*Richter Magnitude+4.8) = 1.68e34
Energy = 10^(1.5*19.6169418+4.8) = 1.68e34 J (5-A)

Although I'm not entirely sure the formula works with something this big.

 

[DarkDragonMedeus]

I'd say it depends on the method as well as the level of the splitting.