- 16,286
- 17,800
Is there a calc/calcs for the creation and/or destruction of Pangaea?
-
This forum is strictly intended to be used by members of the VS Battles wiki. Please only register if you have an autoconfirmed account there, as otherwise your registration will be rejected. If you have already registered once, do not do so again, and contact Antvasima if you encounter any problems.
For instructions regarding the exact procedure to sign up to this forum, please click here. -
We need Patreon donations for this forum to have all of its running costs financially secured.
Community members who help us out will receive badges that give them several different benefits, including the removal of all advertisements in this forum, but donations from non-members are also extremely appreciated.
Please click here for further information, or here to directly visit our Patreon donations page. -
Please click here for information about a large petition to help children in need.
Creating/Destroying Pangaea
- Thread starter LordTracer
- Start date
- 5,296
- 2,000
No calcs as far as I am aware, but is it probably safe to assume it is Tier High 6A to around 5C at the very least.
- 6,448
- 11,215
Imma just calc this rn. According to google, Pangea would've been roughly 148.43 million sqkm. According to this, the average elevation of a continent above sea level is .835 km. That gives us a volume of:
148430000*.835=123939050 km^3 or 1.2393905e+23 cm^3.
Using basic destruction values, we get these:
Frag: 1.2393905e+23*8=9.915124e+23 J (Large Country)
Violent Frag: 1.2393905e+23*69=8.5517944e+24 J (Continent)
Pulverization: 1.2393905e+23*214.35=2.6566335e+25 J (Multi-Continent)
Vaporization: 1.2393905e+23*25700=3.1852336e+27 J (Multi-Continent)
Atomization: 1.2393905e+23*30852.2=3.8237924e+27 J (Multi-Continent)
Sub-Atomic Destruction: 1.2393905e+23*5.403e+13=6.6964269e+36 J (Large Planet)
148430000*.835=123939050 km^3 or 1.2393905e+23 cm^3.
Using basic destruction values, we get these:
Frag: 1.2393905e+23*8=9.915124e+23 J (Large Country)
Violent Frag: 1.2393905e+23*69=8.5517944e+24 J (Continent)
Pulverization: 1.2393905e+23*214.35=2.6566335e+25 J (Multi-Continent)
Vaporization: 1.2393905e+23*25700=3.1852336e+27 J (Multi-Continent)
Atomization: 1.2393905e+23*30852.2=3.8237924e+27 J (Multi-Continent)
Sub-Atomic Destruction: 1.2393905e+23*5.403e+13=6.6964269e+36 J (Large Planet)
- 5,296
- 2,000
I was expecting at least one result of the calc being Moon Level, but I think Atomization is arguably close though.
Not sure about Sub Atomic though, but I assume square inverse law is being used or something if it is a explosion.
- 16,286
- 17,800
- Thread starter
- #5
Nice, thanks for calcing it!
- 35,076
- 41,665
Easier way to do this.
An area of 148.43 million km^2, if turned into a circle, would have a radius of 6873.63 km.
Dump the radius into the nuke calculator and to get a Total Fatality Radius that big, you will need 20096000000 megatons of TNT or 20.096 petatons of TNT (High 6-A). Divide the yield by two if the explosion is non-nuclear, to get 10.048 petatons of TNT (High 6-A).
Using the ground-explosion radius formula...
W = R^3*((27136*P+8649)^(1/2)/13568-93/13568)^2, where W is the yield in tons of TNT, R is the radius in meters, and P is the shockwave pressure in bars, where we generally use 1.37895 bars or 20 psi of pressure. For this specific formula, there is no need to divide the result by 2.
W = 6873630^3*((27136*1.37895+8649)^(1/2)/13568-93/13568)^2= 2.6100208e+16 tons of TNT or 26.100208 petatons of TNT (Still High 6-A)
An area of 148.43 million km^2, if turned into a circle, would have a radius of 6873.63 km.
Dump the radius into the nuke calculator and to get a Total Fatality Radius that big, you will need 20096000000 megatons of TNT or 20.096 petatons of TNT (High 6-A). Divide the yield by two if the explosion is non-nuclear, to get 10.048 petatons of TNT (High 6-A).
Using the ground-explosion radius formula...
W = R^3*((27136*P+8649)^(1/2)/13568-93/13568)^2, where W is the yield in tons of TNT, R is the radius in meters, and P is the shockwave pressure in bars, where we generally use 1.37895 bars or 20 psi of pressure. For this specific formula, there is no need to divide the result by 2.
W = 6873630^3*((27136*1.37895+8649)^(1/2)/13568-93/13568)^2= 2.6100208e+16 tons of TNT or 26.100208 petatons of TNT (Still High 6-A)
- 5,296
- 2,000
Then compared that to the moon: about 14.6 million square miles as Pangea (57.83 million square miles) is actually bigger than the moon in terms of surface area as I assume surface area is talking about the entire moon or something.
- 16,286
- 17,800
- Thread starter
- #8
Would it be possible to do a calc for creating Pangaea as well, or does it only work with destruction?
- 5,296
- 2,000
Creating Pangaea will probably involve creating the continental plates and the lands and stuff.
I will think the creation feat might not been able to being calculated due to the complexity for that matter.
There may been some calcs for that, but I have to look into it as it is likely old info and arguably outdated too.
- 35,076
- 41,665
Abbadon already did the volume, might as well slap continental crust density on it to get the mass. Then we line up the mass with the Creation mass table to see if it fits.
- 35,076
- 41,665
Okay what the ****
Using crust density of 2700 kg/m^3 and Abbadon's volume of 1.2393905e+23 cm^3, using this calculator, I get 3.34635435E+20 kg. Not even Low 6-B according to our Creation Feats chart.
Something tells me we need to account for the other remaining crust underwater as well.
Using crust density of 2700 kg/m^3 and Abbadon's volume of 1.2393905e+23 cm^3, using this calculator, I get 3.34635435E+20 kg. Not even Low 6-B according to our Creation Feats chart.
Something tells me we need to account for the other remaining crust underwater as well.
- 5,296
- 2,000
Ahhh… is surface area volume?
- 35,076
- 41,665
He already multiplied the surface area of 148430000 km^2 with the 0.835 km thickness. Area times thickness is volume.
- 5,296
- 2,000
Huh, make sense, but since we talking about creating the entire supercontinent, we have to factor the soil and stuff? However, that does seem to being a rather underwhelming result if it is being calculated in that way and as far I am aware, there isn’t a single formula for creation that can account for the crust, the soil, plants, and so on in a mathematical sense.
- 35,076
- 41,665
No, there'd be no need to account for soil, since most of that mass will be taken up by the crust.
- 5,296
- 2,000
Fair enough.
Similar threads
