Can you shatter Diamond with Sound?

[CNBA3]

I was wondering, with a feat involving sound, can Diamond shatter from it? if so, how many decibels would it take to do so in order to get energy from it?

 

[Nenhetode]

yes you can, this would depend on the size and shape of the diamond as well as the frequency of the sound wave

 

[CNBA3]

yes you can, this would depend on the size and shape of the diamond as well as the frequency of the sound wave

Okay, thank you, the size i got is 361027.62 m^3, for the frequency, that will be hard if i don’t know how to find wavel to divide by the speed of sound.

 

[CNBA3]

since I can't find anything to give an idea of a amplitude or wavelength, I will be using the shortest length because the feat uses a very loud shout, so it is 1.7 cm.

This would result in 20176.47 hz.

 

[CNBA3]

for the sake of consistenty, I will be using 2.74 meter for wavelength with sound at room temperature.

the frequency would be 125.18248175182 hertz

So what would be the next step, what am I to do with the size and the frequency?

 

[CNBA3]

Bump

 

[Nenhetode]

for the sake of consistenty, I will be using 2.74 meter for wavelength with sound at room temperature.

the frequency would be 125.18248175182 hertz

So what would be the next step, what am I to do with the size and the frequency?

calculate the energy of the sound wave
energy = (amplitude)^2 * (1/2) * speed of sound * frequency

 

[CNBA3]

calculate the energy of the sound wave
energy = (amplitude)^2 * (1/2) * speed of sound * frequency

Okay thanks, so what I found is (6.85 meters)^2*(1/2)*343 m/s*125.18248175182 Hertz = 1007369.5625

 

[CNBA3]

and so using information from the wavelength from frequency thread,

with also finding amplitude https://www.easycalculation.com/physics/electromagnetism/amplitude-of-wave-calculator.php

the formula turned out to be (8575 dB)^2 * (1/2) * 343 m/s * .2 Hz