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Can anyone debunk large star enel?

isee

isee

273
108
Voltage is the ratio of electric potential energy to charge


(Voltage)V = J/C





[Lowest stated quantitative output of joules made by Enel]


1 million volts


Pauling, Linus. College Chemistry. San Francisco: Freeman, 1964:


Radius of an electron = 2.82 × 10-15 m


V = 9.39368373E-44 m














https://m.imgur.com/DQStYDy?r


https://m.imgur.com/jwHmmtd


Enel = 266 cm


Upper body = 50% body height (133 cm)Enel on thrown (Enel's upper body) = 8px {142px panel height}


→ 133/8 (1px: 16.625 cm)


Thrown height = 133px = 2,211.125 cm = 22.11125 m


Backboard thrown = 104px = 1,729 cm


Backboard thrown 2 = 9px {panel height 142px}


Buddha ship head = 86px


/ 16,521.6 cm = 165.216 m


Buddha ship head 2 = 21px (165.216 m)


[panel height 150px, length = 231px]


(= 7.8674286 m / px)


Ship width = 155px


= 1,219.451433 m


Ship = 18px (1px: 67.74730184 m)


G.Jack diameter = 20px = 1,294.9460368 m


Ship = 18px (1px: 67.74730184 m)


G.Jack diameter = 20px = 1,294.9460368 m


Giant Jack shot ~


Diameter = 5px (1px: 258.9892074 m)


Height = 103px


= 26,675.883622 m


https://m.imgur.com/zHtRhaK


https://m.imgur.com/NTf6TRZ


Current height = 71px / 26,675.883622 m


[ 1px / 375.716670732 m ]


Current diameter = 4px / 1,502.86668293 m


Radius = 751.433341465 m


V = π r^2 h


V = 4.73205e10 m3


4.73205e10 / 9.39368373e-44


qe- = 5.0374806e53


qC = 8.0728856e34


V = J/C


J = V × C


1e8 × 8.0728856e34 = 8.0728856e42 J


(×17)= 1.3723906e+44


Large Star Level
 
isee said:
Voltage is the ratio of electric potential energy to charge


(Voltage)V = J/C





[Lowest stated quantitative output of joules made by Enel]


1 million volts


Pauling, Linus. College Chemistry. San Francisco: Freeman, 1964:


Radius of an electron = 2.82 × 10-15 m


V = 9.39368373E-44 m














https://m.imgur.com/DQStYDy?r


https://m.imgur.com/jwHmmtd


Enel = 266 cm


Upper body = 50% body height (133 cm)Enel on thrown (Enel's upper body) = 8px {142px panel height}


→ 133/8 (1px: 16.625 cm)


Thrown height = 133px = 2,211.125 cm = 22.11125 m


Backboard thrown = 104px = 1,729 cm


Backboard thrown 2 = 9px {panel height 142px}


Buddha ship head = 86px


/ 16,521.6 cm = 165.216 m


Buddha ship head 2 = 21px (165.216 m)


[panel height 150px, length = 231px]


(= 7.8674286 m / px)


Ship width = 155px


= 1,219.451433 m


Ship = 18px (1px: 67.74730184 m)


G.Jack diameter = 20px = 1,294.9460368 m


Ship = 18px (1px: 67.74730184 m)


G.Jack diameter = 20px = 1,294.9460368 m


Giant Jack shot ~


Diameter = 5px (1px: 258.9892074 m)


Height = 103px


= 26,675.883622 m


https://m.imgur.com/zHtRhaK


https://m.imgur.com/NTf6TRZ


Current height = 71px / 26,675.883622 m


[ 1px / 375.716670732 m ]


Current diameter = 4px / 1,502.86668293 m


Radius = 751.433341465 m


V = π r^2 h


V = 4.73205e10 m3


4.73205e10 / 9.39368373e-44


qe- = 5.0374806e53
Click to expand...

Ignoring the other problems with this calc, Lightning isn't a solid mass of stationary electrons. You can't just fill up the volume of a bolt with electron volumes to get the number of electrons traveling through it.

But whatever, let's say you can do that- the calc is still massively highballed.

A typical bolt of lightning is about 2.5 centimeters wide and 2.5 miles tall (roughly 4 kilometers) on average, and may transfer 1.11*10^20 electrons through it. That's an "electron density" (not really a thing but we're ignoring that) of- assuming roughly cylindrical lightning-

(1.11*10^20) / (0.025/2)^2*Pi*4022.5 = 8.9773649*10^27 electrons per cubic meter

By literally just "filling up" a volume with electron volumes, you have assumed an electron density of- 1/9.39368373*10^(-44) = 1.0645451*10^45 electrons per cubic meter, making it-

(1.0645451*10^45) / (8.9773649*10^27) = 1.18581021*10^17 times more "electron dense" than actual lightning, meaning even if the rest of the math stayed the same, the result should still be over 118 quadrillion times lower.

At 5*10^53 electrons, you calced that one bolt of lightning to have 100 times more electrons inside of it than there are electrons inside the Earth. (Earth is roughly 1.35 * 10^50 electrons, most atomic elements of which only has around a dozen or two electrons, meaning it'll be between 1 * 10^50 and 3 * 10^51 electrons)

Now, that still results in Enel having an AP of 276.6 Petatons, which is still way too high, but I can't see what else is wrong with your calc here, because you did not show the math for what you did afterward.
 
ElajRuengies said:
Ignoring the other problems with this calc, Lightning isn't a solid mass of stationary electrons. You can't just fill up the volume of a bolt with electron volumes to get the number of electrons traveling through it.

But whatever, let's say you can do that- the calc is still massively highballed.

A typical bolt of lightning is about 2.5 centimeters wide and 2.5 miles tall (roughly 4 kilometers) on average, and may transfer 1.11*10^20 electrons through it. That's an "electron density" (not really a thing but we're ignoring that) of- assuming roughly cylindrical lightning-

(1.11*10^20) / (0.025/2)^2*Pi*4022.5 = 8.9773649*10^27 electrons per cubic meter

By literally just "filling up" a volume with electron volumes, you have assumed an electron density of- 1/9.39368373*10^(-44) = 1.0645451*10^45 electrons per cubic meter, making it-

(1.0645451*10^45) / (8.9773649*10^27) = 1.18581021*10^17 times more "electron dense" than actual lightning, meaning even if the rest of the math stayed the same, the result should still be over 118 quadrillion times lower.

At 5*10^53 electrons, you calced that one bolt of lightning to have 100 times more electrons inside of it than there are electrons inside the Earth. (Earth is roughly 1.35 * 10^50 electrons, most atomic elements of which only has around a dozen or two electrons, meaning it'll be between 1 * 10^50 and 3 * 10^51 electrons)

Now, that still results in Enel having an AP of 276.6 Petatons, which is still way too high, but I can't see what else is wrong with your calc here, because you did not show the math for what you did afterward.
Click to expand...
These are not my calc
 
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