Calculations from Yale University about Solar Luminosity

[Matthew_Schroeder]

http://www.astro.yale.edu/astro120/Astro120-HW3-solutions-2016.pdf

So, according to these calculations from the Yale University Department of Astronomy, a star like our Sun releases 1.38 ┬À 10^28 J sÔêÆ1 through its luminosity alone, which is well into Multi-Continent level.

According to it, when our sun becomes a Red Giant Star, its luminosity will also increase by a factor of roughly x2000 times, and according to it, our sun will be releasing 7.8 × 10^29(J/s) through its new luminosity.

This should help us with rating characters who can survive inside stars, as they will be constantly exposed to this levels of energies.

 

[WeeklyBattles]

High 6-A Garnet...

 

[LordXcano]

@Weekly

Don't jump the gun just yet. For two reasons:

• Garnet can survive in the Sun because of her Ruby component being particularly heat resistant, it's more a hax type thing

• While the Sun releases this level of energy a whole lot, that's the energy from the entire surface area, a 1.8 m^2 person would not be tanking this much energy

 

[CrossverseCrisis]

Cool~

So the luminousity becomes like.....Moon/Small Planet level in energy, ye?

This looks really cool to use.

 

[Colonel_Krukov]

Good find @Matt

If this is accepted, who needs to be upgraded?

 

[Byakuya_"Senbonzakura"_Kuchiki]

Yo this is good.

This'll be great if this gets accepted and whoever is gonna get upgraded.

 

[VenomElite]

Mm. This looks alright.

 

[Matthew_Schroeder]

@Xcano

Are you sure? This is the energy released in the surface area alone, we are talking about those who survive inside stars.

 

[WeeklyBattles]

Plus wouldnt we have to factor in the gravity of the sun as well? Well...not in Garnet's case but for this to apply to anyone as well?

 

[Matthew_Schroeder]

Yes, we need to factor in heat, luminosity, gravity, a lot of different factors.

 

[Antoniofer]

But this isn't something that new, we already known that the power of our sun reach up to 4.1*10ˆ26 Watts, at the end, we use what Xcano already say: using temperature of the surface and the character's surface. Tho, I don't like that kind of convertion, since it makes bigger characters stronger than the smaller ones even when they resisted the same temperature.

 

[LordXcano]

For reference, the Sun's surface area is 1,520,000 million m^2, while a human is only 1.8 m^2. This means that a human being would only be taking 1.184e-10% this energy. That comes out to just 3.905 Megatons, Small City level. Not sure how this stacks up against our current value though.

 

[Matthew_Schroeder]

@Xcano

Correct me if I'm wrong, but the sun releases its luminosity due to constantly performing nuclear-fusion in it's core. These energies are then released through the sun's area producing its luminosity.

So if a character can survive the core of a star, he would be exposed to pretty much all of this.

 

[LordXcano]

The actual nuclear fusion would be much higher than its luminosity. I was actually planning on doing something for the nuclear fusion at the core.

 

[Matthew_Schroeder]

That would help rate a whole bunch of characters, actually. Being inside the core of a star is an incredibly common feat in fiction.

 

[LordXcano]

https://vsbattles.fandom.com/wiki/User_blog:LordXcano/Tanking_the_Core_of_the_Su

 

[CrossverseCrisis]

Hooo.....

 

[Matthew_Schroeder]

Didn't DontTalk said he was going to do a calc himself about this? And said it would be Low 6-B or something.

 

[Joseph619]

https://vsbattles.fandom.com/wiki/User_blog:LordXcano/Tanking_the_Core_of_the_Su

This would mean a lot of fodders would survive in core of Sun, and in fiction it's treated impressive for much, much stronger characters to survive in Sun's core.

 

[Matthew_Schroeder]

I'm not sure it is entirely representative.

 

[DanFlsamual21]

Is there a page that lists random things like this for durability. Like just anything in general

 

[Antvasima]

I would appreciate if somebody can ask other calc group members about checking up LordXcano's calculation.

If they accept it, we can probably let it replace the links to DontTalk's old calculation. However, I no longer remember where we link to it.

 

[The_Living_Tribunal1]

Hold on. That is the total amount of solar energy released per second. Being inside the sun doesnt necessarily mean that you get that energy the sun releases. Use that to find the energy density, then use the surface area of the body affected to ind the energy tanked. Of course being in the centre of the sun is a different thing altogether.


Also, I remember doing homework problems like that, and like in all homework problems in astronomy assignments, rough approximations are used. So its better to use a scientific paper to find the exact value instead of an approximate one from a homework assignment.


Anyway, the core itself makes about 3.86*10^26 J/s. BUT, this is the energy made by the ENTIRE core at once, so if someone if on the core of the sun, then take the ratio of the core's area and the body's area, then divide the core energy production per second by this ratio to get energy tanked per second.

Similarly, for anyone right on the surface of the sun, use the same total surface to body area ratio to find the energy tanked per second.

 

[Antvasima]

I think that TLT1 makes sense.

 

[LordXcano]

@TLT1

That's what I did with the calc. Got Building level and City Block level for using the power production and the luminosity respectively. This is in the core, of course. But I also got Large Town assuming the pressure from the core was applied to their entire body volume.

 

[Antvasima]

So, should we use LordXcano's calculation, or DontTalk's? No calc group member seems to have commented on the former.

 

[Matthew_Schroeder]

Some people told me that DontTalk wanted to recalc it, that or somebody else. And that they were predicting a Country-level result.

 

[Antvasima]

Okay. I will ask him about it.

 

[DontTalk]

Some people told me that DontTalk wanted to recalc it, that or somebody else. And that they were predicting a Country-level result.

Nah didn't want to recalc it. My current calc has a J/s result that is Small Country level, though that isn't the used one.

Honestly I am not sure wether LordXcanos J/s versions might not be better than my J/s versions (if we want to take J/s versions), given that mine are a lot more theoretical.

Mine do consider energy transmission through conducation additionally to radiation, but that influence came out minor so that it isn't the best point.


I think the energy value shouldn't drop below the energy intake value, though.

 

[Matthew_Schroeder]

@DontTalk

Can we see your calculation?

 

[DontTalk]

https://vsbattles.fandom.com/wiki/User_blogontTalk/Durability_required_to_resist_the_heat_of_the_su

 

[Gwynbleiddd]

I think that using the amount of energy that would hit the target inside the core would be a better approach, since this is how we treat durability in general.

Also TLT1 is right, the total energy released by a star would have very little to do with surviving inside its core.

 

[Antvasima]

I think that Gwynbleiddd makes sense.