Calculating creation feats

[CNBA3]

I wish to find out what the best way to find the energy needed to create something, is it basically just finding the mass of something created?

I am trying to find the feat measuring the size of a polar glacier created with 15 million mi^2 and is 20 meters thick

 

[CNBA3]

after finding the mass of the Glacier, it is 7.10675E+17 kg of ice, I don't know if that translates to anything or if it requires more info.

 

[CNBA3]

first finding the volume is pi * 3512222 m^2 * 20 m = 7.75E+14 m^3, and the density of glaciers are 917 kg/m^3, multiplying both gets the answer above.

 

[Jobbo]

You could use mass energy conversion to find the required energy, just multiply the mass by c^2. That leads to some pretty colossal results and generally isn't accepted by the wiki, though.

 

[CNBA3]

You could use mass energy conversion to find the required energy, just multiply the mass by c^2. That leads to some pretty colossal results and generally isn't accepted by the wiki, though.

Ok, though would that depend on the verse in question or just generally not accepted at all?

 

[Jobbo]

Generally not at all. It pretty much always leads to colossal outliers. For instance, your glacier creation feat would be Large Planet level.

 

[CNBA3]

Generally not at all. It pretty much always leads to colossal outliers. For instance, your glacier creation feat would be Large Planet level.

Ok, it's just that it is from a verse where a rocket launcher has enough energy yield that it can destroy a earth sized planet but has safety measures to ensure it doesn't happen.

 

[CNBA3]

Bump

 

[CNBA3]

Bump

 

[Jobbo]

What's the matter?

 

[CNBA3]

What's the matter?

No, just wondering, that if we do not use e=mc^2, do we just go by what the total mass is comparing to joules?

 

[Jobbo]

Yeah. Unless the glacier was created by cooling a pre-existing substance, in that case you'd need to find the specific heat of that substance.

 

[CNBA3]

Yeah. Unless the glacier was created by cooling a pre-existing substance, in that case you'd need to find the specific heat of that substance.

Ok, though it would be difficult because the feat was just done by someone that just says it was created, the only other information is that it is on mars and in the northern polar ice caps

 

[CNBA3]

I made a mistake that it wasn't mi^2 but just miles

So changing it up I got 8.39401E+27 grams of mass for the glacier

 

[CNBA3]

bump

 

[CNBA3]

Bump

 

[Assaltwaffle]

Such a glacier is significantly heavier than the planet, and many many time larger. That said, such an object outright wouldn't work by real standards.

Being obscenely long but very thin in comparison would make the glacier incredibly unstable; it would likely be destroyed by its own gravity.

 

[CNBA3]

It is not created naturally if that makes any difference, it would be on mars as well

 

[Jobbo]

Mars would be destroyed.

 

[Assaltwaffle]

This thing is getting close to Mars with that kind of radius. If the glacier started at Earth such a massive sheet of ice would almost make it to the red planet.

 

[CNBA3]

ere is the quote if it is subject to mistranslation "Polar landmass of mars spans nearly 15 million kilometers with ridges up to 20 meters thick."

I think that could have been area instead of length, and it has a density that makes scanning difficult a minute ago

 

[Jobbo]

That's definitely area.

 

[Kepekley23]

How can that be if Mars is just an ornament attached to the dome that covers the Earth?

But seriously, that thickness poses a problem. This thing is large enough to collapse on itself.

 

[CNBA3]

How can that be if Mars is just an ornament attached to the dome that covers the Earth?

But seriously, that thickness poses a problem. This thing is large enough to collapse on itself.

I wonder if that quote is just referring to any glacier ridges that are higher than it's regular thickness

 

[CNBA3]

So after going a bit of calving with the thickness of both the Martian glacier and adding the ridges (110m at least)

The mass should be 1.53139E+21 g

 

[CNBA3]

Should I use this as reference to calc this feat?

https://www.narutoforums.org/xfa-bl...hit-arount-the-power-levels-fairy-fail.35862/