calc for stopping the movement of the sun?

[Shiraito983]

^

 

[Reiner04]

What exactly stopping sun from moving mean here? If u mean it's stopped rotating then;
0.5*I*ω² would be the energy required to stop it's rotational motion. ω = 2π/25*24*60*60 since ig sun completes it's one rotation around it's own Axis in 25 days. "I" is the moment of inertia of sun along it's axis, which would be (2/5)*(mass of sun)*radius of sun².

If it's complete stop so that it's not even doing it's transitional motion around the galactic center then;

K.E = 0.5 (mass of sun*linear velocity of sun² + moment of inertia along it's centeral axis*ω²)

 

[TWILIGHT-OP]

What exactly stopping sun from moving mean here? If u mean it's stopped rotating then;
0.5*I*ω² would be the energy required to stop it's rotational motion. ω = 2π/25*24*60*60 since ig sun completes it's one rotation around it's own Axis in 25 days. "I" is the moment of inertia of sun along it's axis, which would be (2/5)*(mass of sun)*radius of sun².

If it's complete stop so that it's not even doing it's transitional motion around the galactic center then;

K.E = 0.5 (mass of sun*linear velocity of sun² + moment of inertia along it's centeral axis*ω²)

You should become CGM

 

[Reiner04]

You should become CGM

I'm not good enough. Just happen to know it.

 

[Shiraito983]

What exactly stopping sun from moving mean here? If u mean it's stopped rotating then;
0.5*I*ω² would be the energy required to stop it's rotational motion. ω = 2π/25*24*60*60 since ig sun completes it's one rotation around it's own Axis in 25 days. "I" is the moment of inertia of sun along it's axis, which would be (2/5)*(mass of sun)*radius of sun².

If it's complete stop so that it's not even doing it's transitional motion around the galactic center then;

K.E = 0.5 (mass of sun*linear velocity of sun² + moment of inertia along it's centeral axis*ω²)

i am doing it right?

1.989e+30 * 1.259e+16 + 1.085e+42 * ω² = 6.35751677x10^48 J / 0.5 = 1.2715034e+49 J

linear velocity of the sun = 1.259x10^16 m/s.
moment of inertia along it's centeral axis =1.085x10^42 kg m^2

these info came from ai btw since i cant search in google

 

[Reiner04]

Moment of inertia of sun for me coming out to be= (2/5)*1.9821*10^30*696340000² = 3.84439708407504e+47 kgm²
So it's rotational K.E:
0.5*(3.84439708407504e+47)*(2π/(27*24*60*60))² = 1.394450065236917e+36

Ig transitional KE: 0.5*mass of sun*(230000)² [since Google shows me it's transitional velocity is 230 km/s, so I suggest check and source them just incase]
Then just add transitional and rotational KE u got above.

 

[CNBA3]

What exactly stopping sun from moving mean here? If u mean it's stopped rotating then;
0.5*I*ω² would be the energy required to stop it's rotational motion. ω = 2π/25*24*60*60 since ig sun completes it's one rotation around it's own Axis in 25 days. "I" is the moment of inertia of sun along it's axis, which would be (2/5)*(mass of sun)*radius of sun².

If it's complete stop so that it's not even doing it's transitional motion around the galactic center then;

K.E = 0.5 (mass of sun*linear velocity of sun² + moment of inertia along it's centeral axis*ω²)

When using those values for mass, speed and radius, do you use kg, m/s and meters?

and for "ω", how do you get that for rotation angle for something that happens in seconds?

 

[Reiner04]

When using those values for mass, speed and radius, do you use kg, m/s and meters?

Yeah & radian/sec.

 

[CNBA3]

Yeah & radian/sec.

okay thanks, last bit.

for "ω", how do you get that for rotation angle for something that happens in seconds?

 

[Reiner04]

okay thanks, last bit.

for "ω", how do you get that for rotation angle for something that happens in seconds?

ω = angular velocity= Angle moved (in radians)/time taken. Same as linear velocity= Distance moved/time taken.

ω Also equals to linear velocity/radius.
Like let's say moon speed is 300m/s around the earth then it's angular velocity would be 300/distance between Earth and moon (basically radius of circle it makes).