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Atmospheric Reentry Velocity

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I want to calculate the kinetic energy of a character over 60 meters that orbited the Earth and then crashed into it?

What is the speed I have to use?
 
Usually we use 11 km/s, but depending on the time of day speed could vary from 20-72 km/s, but your mileage may vary. That being said, I forgot what time of day the 20-72 km/s values are used for.
 
Usually we use 11 km/s, but depending on the time of day speed could vary from 20-72 km/s, but your mileage may vary. That being said, I forgot what time of day the 20-72 km/s values are used for.
Didn't we scrap that time of the day idea again?
IIRC that was about which side the approach was from (day or nightside) for a meteor coming from far in the solar system and not about where it landed.
 
Didn't we scrap that time of the day idea again?
IIRC that was about which side the approach was from (day or nightside) for a meteor coming from far in the solar system and not about where it landed.
Did we? I don't remember. Nor do I remember anything about the spot where it lands.

So it's about from which side the approach comes in then?
 
I can't find the thread/article about the night/day velocities anymore, so I can't check to say for sure.
 
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