3-A question

[Cosmic_King_of_SAO]

If you destroy something with the mass of the entire universe (just the physical matter part), does that make you universal? For example, a ball that's as heavy as the universe itself.

 

[Confluctor]

Yeah, I am pretty sure it qualifies for 3-A

 

[Cosmic_King_of_SAO]

Yeah, I am pretty sure it qualifies for 3-A

Thanks for answering.

 

[ATalentedMaid]

Yes it is.

 

[Arceus0x]

Like every planet galaxy and stuff like that? Cause pretty sure that would be like 3-B

 

[Emirp sumitpo]

If we're talking about every physical object in the universe combined, then that would be around 3-C to 3-B IIRC

 

[GilverTheProtoAngelo]

I have heard 4A-3C....though should be 3B imo.

 

[GilverTheProtoAngelo]

I mean does the space have ""mass"" though??
I heard they have energy or something due to Quantum Mechanics shenanigans or something.....is that true??
Also what about Dark Matter and stuff??

 

[Bernkastelll]

I mean does the space have ""mass"" though??

idk, isnt the vacuum just...nothing? perhaps it has no mass

 

[GilverTheProtoAngelo]

idk, isnt the vacuum just...nothing? perhaps it has no mass

When space is empty its called vaccum.
Space itself is different deal though....

 

[Blahblah9755]

That would not inherently be 3-A.

For reference, I’ll calc this as a ball with the density of the sun.
M= 1.5e+53kg
Density = 1.41 g/cc
Volume = 1.06382979e+50m^3
Radius = 2.93941685e+16 m
GBE = 3G*(1.5e+53 kg)^2/(5* 2.93941685e+16 m) = 3.06523656e+79 Joules
3-B.
The value here would be inversely proportional to the radius, so with a dense enough ball this could reach 3-A.

 

[GilverTheProtoAngelo]

There is this...

Energy to destroy matter of the observable universe

vsbattles.fandom.com

 

[Blahblah9755]

That doesn’t answer the question though. It calculates actually busting the matter of the universe spread as it is now.

 

[Cosmic_King_of_SAO]

That would not inherently be 3-A.

For reference, I’ll calc this as a ball with the density of the sun.
M= 1.5e+53kg
Density = 1.41 g/cc
Volume = 1.06382979e+50m^3
Radius = 2.93941685e+16 m
GBE = 3G*(1.5e+53 kg)^2/(5* 2.93941685e+16 m) = 3.06523656e+79 Joules
3-B.
The value here would be inversely proportional to the radius, so with a dense enough ball this could reach 3-A.

I see, thank you.

Also thanks to everyone for answering.

 

[GilverTheProtoAngelo]

That doesn’t answer the question though. It calculates actually busting the matter of the universe spread as it is now.

I mean tweaking the value a bit with different, probably bigger/denser Celestial body at the edge of universe will increase the result to desirable lvl.