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Reality Quest Discussion Thread

Definitely full Cold Resistance, wouldn't see why it'd be limited when his skin isn't fazed at all. Don't think the "Saving Dowan from the nitrogen" can be calculated too
 
Definitely full Cold Resistance, wouldn't see why it'd be limited when his skin isn't fazed at all. Don't think the "Saving Dowan from the nitrogen" can be calculated too
Only asking because I've never seen tanking Liquid Nitrogen feats in any series lol
 
Dang. I even saw that his attack was so strong, that it caused the interior to hit a high-pressure state and the room hit over 3000 degrees Fahreinheit (in the dialogue itself)?? Probably going to wait for the official TL, but this seems like something Viott would be more knowledgable on.
 
Yup same. I do not have the skills required to take into account everything that went down in that feat 😭
 
In the official calculator there is actually a thermal calculator. We could in theory plug in -18 (starting heat) and 1880 (final heat) with ice as material. The problem is the actual amount of ice being melted- which does impact the large majority of the result.

We could in theory use air since it's "easier" to get if you have the entire container size but its unfortunately not a value oof
 
In the official calculator there is actually a thermal calculator. We could in theory plug in -18 (starting heat) and 1880 (final heat) with ice as material. The problem is the actual amount of ice being melted- which does impact the large majority of the result.

We could in theory use air since it's "easier" to get if you have the entire container size but its unfortunately not a value oof
Using the density of air in the container (and assuming all of that volume), won't get you that high of a results. Viott says the steel container is compressed, so maybe do that. I'll leave this calculation alone though (unless a full day goes by w/o a calc)
 
What's happening at the end there
aint-nothing-gonna-happen-nothing-happen.png
 
First one ain’t really weight manipulation but everything else is fair. If there wasn’t the dialogue of “dethawing wouldnt revive a fish”, I’d ignore Life M but there is and mans still revived the fish 😭
Idk what to classify it as not gonna lie. He didn't really move at all and people were just incapable of pushing him off his position. We know that the people in RQ dont just drastically become heavier with more power so there is that
 
Idk what to classify it as not gonna lie. He didn't really move at all and people were just incapable of pushing him off his position. We know that the people in RQ dont just drastically become heavier with more power so there is that
That can just be attributed due to Jinoh's own LS that stops the others from moving him.
 
I don't think he resurrected the fishes.
More like, the shockwave he created caused the fishes who's hearts had stopped due to being frozen to restart. (sort of like a defibrillator?)
 
Im not sure we can apply logic to that. The fishes should have been obliterated for all intended purposes and/or fried from the heat

Edit: Unless the fact the ice melted was due to the damage of the refrigerator container itself and not the heat/pressure skyrocketing
 
They would've been fried if they weren't frozen ig?
Maybe it's something like the shockwave's heat negated the liquid nitrogen's freezing effect of the fishes.
 
Yup, something like that would be quite useful, ngl. So far we have:
S1:
  • Beginning of the series
  • Post First training
  • Post Dragon Nest
S2:
  • Post Challenge Tower
  • Post Extraordinary Body
S3:
- Likely, but not guaranteed, another key

Though we more than likely have a lot of time since I feel like the series will undergo another year or so hiatus for the new season anyway
 
In the official calculator there is actually a thermal calculator. We could in theory plug in -18 (starting heat) and 1880 (final heat) with ice as material. The problem is the actual amount of ice being melted- which does impact the large majority of the result.

We could in theory use air since it's "easier" to get if you have the entire container size but its unfortunately not a value oof
Why not -195 C, The fish was still preserved before the attack. If the chamber wasn’t still under cryogenic conditions, the fish would have thawed long before the temperature increase
 
Why not -195 C, The fish was still preserved before the attack. If the chamber wasn’t still under cryogenic conditions, the fish would have thawed long before the temperature increase
Because -196 is the temperature of the Liquid Nitrogen, not the temperature of the container itself. Liquid nitrogen is only needed in the first step of the freezing process (Flash Freeze), the -18 degrees is needed to maintain the ice after

EDIT: Just tested with the calculator. Assuming it is a Chum Salmon (Fairily common in Korea), at least 15 shown with an average weight of 5.2 kgs per fish and assuming we have a heating from -196 to 1880, the result is only 338.4295 MJs (9-A), it'd be just a supporting feat at best. Maybe I can try and check it by using the air volume instead of the ice
 
Last edited:
Roughly the same result.

Using CatLover's container dimensions, it comes out at approximately 352 MJ to heat up the air in the container to 143.46 m^3 (Assumed 80% only, since it was largely empty). 393 MJ if you take into account that the air pressure is not constant due to the heating process.
 
Because -196 is the temperature of the Liquid Nitrogen, not the temperature of the container itself. Liquid nitrogen is only needed in the first step of the freezing process (Flash Freeze), the -18 degrees is needed to maintain the ice after
If that’s the case, then the fish shouldn’t have remained cryopreserved. If it had been sitting at around −18 C after the initial freezing, its temperature would increase and it would no longer remain in the same cryogenic state. So it makes more sense that the chamber was still maintaining the same cryogenic temperature as liquid nitrogen, or at least a temperature capable of keeping it cryopreserved.
 
If that’s the case, then the fish shouldn’t have remained cryopreserved. If it had been sitting at around −18 C after the initial freezing, its temperature would increase and it would no longer remain in the same cryogenic state. So it makes more sense that the chamber was still maintaining the same cryogenic temperature as liquid nitrogen, or at least a temperature capable of keeping it cryopreserved.
Ice only needs subzero temperatures to be maintained though it doesn't need to be that cold
 
Ice only needs subzero temperatures to be maintained though it doesn't need to be that cold
Again to keep the fish in a cryogenic state, it needs to be at -150 C or colder, If the fish was frozen and then kept inside a refrigerator container at -18 C, the heat from the refrigerator would transfer into the fish, It will completely lose its cryogenic status wich damages the cellular tissue and ruins its chance of ever being revived, It will then just be like the bags of frozen fish you buy at a grocery store.

So, the logical answer is that the temperature of the container should be between -150 C and -196 C
 
Again to keep the fish in a cryogenic state, it needs to be at -150 C or colder, If the fish was frozen and then kept inside a refrigerator container at -18 C, the heat from the refrigerator would transfer into the fish, It will completely lose its cryogenic status wich damages the cellular tissue and ruins its chance of ever being revived, It will then just be like the bags of frozen fish you buy at a grocery store.

So, the logical answer is that the temperature of the container should be between -150 C and -196 C
So I did some research on how adiabatic compression is calculated, It uses the same change in temperature formula as the one on the VS Battles Calculation Guide.
The only difference is that, because this feat takes place inside a completely sealed container, c refers to the constant volume specific heat capacity (Cv).

E = McΔT

1. Mass = Volume × Density
a. Volume: Rectangular prism = 3.97x12.4x4.65= 228.91
b. Density: Nitrogen gas density at cryogenic temperature = 4.56
c. Mass = 228.91x4.56 = 1044

2. C= 743

3. Temperature Change= 1880-(-196) = 2076

4. E = 1044x743x2076= 1610336592 j or 0.385 tons of TNT

@CatLover313
 
Again to keep the fish in a cryogenic state, it needs to be at -150 C or colder, If the fish was frozen and then kept inside a refrigerator container at -18 C, the heat from the refrigerator would transfer into the fish, It will completely lose its cryogenic status wich damages the cellular tissue and ruins its chance of ever being revived, It will then just be like the bags of frozen fish you buy at a grocery store.

So, the logical answer is that the temperature of the container should be between -150 C and -196 C
Tried to look for it more in-depth, I think you are right
 
So I did some research on how adiabatic compression is calculated, It uses the same change in temperature formula as the one on the VS Battles Calculation Guide.
The only difference is that, because this feat takes place inside a completely sealed container, c refers to the constant volume specific heat capacity (Cv).

E = McΔT

1. Mass = Volume × Density
a. Volume: Rectangular prism = 3.97x12.4x4.65= 228.91
b. Density: Nitrogen gas density at cryogenic temperature = 4.56
c. Mass = 228.91x4.56 = 1044

2. C= 743

3. Temperature Change= 1880-(-196) = 2076

4. E = 1044x743x2076= 1610336592 j or 0.385 tons of TNT

@CatLover313
I’ll add this as a “2nd end” and ask too if it can be stacked on top of the compression just because the compression happens and then the temperature rises. Though I’ll need to change the volume because well need to subtract the thickness of the container from all 3 dimensions.
 
I was thinking, could we scale the characters in Representative Tier to this feat by Sun-Jae?

We know Sun-Jae FAR upscales Dowan's 3 GJ feat, so the fact that Sun-Jae mogging the fodder didn't kill him demonstrates that this feat was Sun-Jae holding back. This makes a "Casual" Sun-Jae scale to at least 130.607 Megajoules.

Dae-Bujin was able to tank several non-lethal (i.e. 'casual') hits from a Synced Dowan.
Should Bujin's durability scale to the casual Sun-Jae feat and everyone who can hurt Bujin should have an AP of 130 MJ?
 
Not 100% sure though I'm neither opposite or for this possible chainscale. The reasoning is sound its just we dont know how hard Sunjae actually hit the guy compared to how hard Sunjae Synch actually hit Bujin
 
Not 100% sure though I'm neither opposite or for this possible chainscale. The reasoning is sound its just we dont know how hard Sunjae actually hit the guy compared to how hard Sunjae Synch actually hit Bujin
Going by context, Sun-Jae was fighting to capture the traitors. All he did was neutralize his opponents and deliver them to HQ.
Dowan on the other hand was fighting to win, he was going to break Bujin's arm so it's safe to assume he was more than willing to hurt him.

I think this stronger intent to hurt the opponent + the fact that Dowan hit Bujin multiple times should be enough to scale his durability to the 130 MJ feat.
 
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