How to calculate a black hole?

[ShionAH]

https://cdn.**********.com/attachments/1079096886436298864/1079114739243827290/image.png


Average Basketbol Hoop Height = 3.05m or 343 Pixel (Red Line)
3.05 / 343 = 0.00889212827 = 1 Pixel
Necati's Height = 1.68m or 190 Pixel (Blue Line)


https://cdn.**********.com/attachments/1079096886436298864/1079115462673190912/image.png



Necati's Height = 1.68m or 422 Pixel (Blue Line)
1.68 / 422 = 0.00398104265 = 1 Pixel
Black Hole = 0.45m or 114 Pixel (Red Line)

After this how can I calculate the blackholes mass to learn the AP it would give?

Also a character kicks it can I use the blackholes mass to calculate that AP as well?

 

[Dragonite007]

Black Hole Feats in Fiction

When it comes to the topic of black holes there are a lot of common misconceptions about their nature and through that also misconceptions about the evaluation of feats involving them. Generally, black holes are often depicted wrong in works of fiction. While a completely correct depiction can...

vsbattles.fandom.com

 

[ShionAH]

Black Hole Feats in Fiction

When it comes to the topic of black holes there are a lot of common misconceptions about their nature and through that also misconceptions about the evaluation of feats involving them. Generally, black holes are often depicted wrong in works of fiction. While a completely correct depiction can...

vsbattles.fandom.com

Too complicated what do I do after I find the size?

 

[Dragonite007]

Your Black Hole is 0,45m. So is Large Planet level (5-A)

 

[ShionAH]

Your Black Hole is 0,45m. So os Large Planet level (5-A)

Question is kicking that blackhole considered 5-A as well?

 

[Dragonite007]

Question is kicking that blackhole considered 5-A as well?

Yes

 

[ShionAH]

Yes

I need the blackholes mass so I can calculate the kinetic energy of the kick

 

[ShionAH]

Yes

How can I learn the mass?

 

[Dragonite007]

3,0310456e+28 kg

 

[ShionAH]

3,0310456e+28 kg

Wow! How did you do that?

 

[ShionAH]

3,0310456e+28 kg

Can I see your calculation

 

[ZawierJ]

3,0310456e+28 kg

Can you send the calculation?

 

[Ikelaggan]

M = (R*c^2)/(2*G)
This is how you solve for mass.

 

[Dragonite007]

Can I see your calculation

My bad.
Is 1.5164223905218959x 10^26kg, I forgot to use put the sphere radio

You can use this calculator

Black Holes

 

[ZawierJ]

My bad.
Is 1.5164223905218959x 10^26kg, I forgot to use put the sphere radio

You can use this calculator

Black Holes

I can't use this website something like this happens after typing the numbers

 

[ZawierJ]

M = (R*c^2)/(2*G)
This is how you solve for mass.

(0.64285714285 * 299792458^2) / (2 * 6.67x10^-11) = 4.3311183e+26kg
0.64285714285 This is radius of the Black Hole, i found the mass like that is it correct?

 

[Second22]

Formula: ((299792458^2/(2*6.674*10^-11))/(5.972*10^24))*(2.487*10^32) * radius in meters = energy in joules

 

[ZawierJ]

Formula: ((299792458^2/(2*6.674*10^-11))/(5.972*10^24))*(2.487*10^32) * radius in meters = energy in joules

I know this formula but i'm asking for mass

 

[Second22]

I know this formula but i'm asking for mass

Sorry, I just read the OP.

0.64285714285

Where did you get this number from?

 

[ShionAH]

Where did you get this number from?

We found a scan where the blackhole is much bigger

 

[ZawierJ]

Where did you get this number from?

The Calculation is here you can take a look. I made it for see my mistakes.

 

[Second22]

We found a scan where the blackhole is much bigger

Yeah. Then 4.3311183e+26kg corrected

The Calculation is here you can take a look. I made it for see my mistakes.

You have to use this ((299792458^2/(2*6.674*10^-11))/(5.972*10^24))*(2.487*10^32) * radius in meters = energy in joules. It’s for black holes less than 1477m in radius

 

[Second22]

((299792458^2/(2*6.674*10^-11))/(5.972*10^24))*(2.487*10^32) * 0.64285714285 = 1.8025846e+34 J
Or

4.3311183e+26 kg (black hole mass) / 5.97219e+24 kg (Earth mass) * 2.487e32 J (Earth GBE) = 1.8036083e+34

get similar results

 

[ZawierJ]

((299792458^2/(2*6.674*10^-11))/(5.972*10^24))*(2.487*10^32) * 0.64285714285 = 1.8025846e+34 J
Or

4.3311183e+26 kg (black hole mass) / 5.97219e+24 kg (Earth mass) * 2.487e32 J (Earth GBE) = 1.8036083e+34

get similar results

There are different results. Why did it change?

 

[Second22]

There are different results. Why did it change?

It's just a slightly different decimal point.

 

[Second22]

If you think about the decimal point being slightly different. I will change it.

(0.64285714285 * 299792458^2) / (2 * 6.674x10^-11) = 4.3285225e+26 Kg

4.3285225e+26 / 5.972e+24 * 2.487e32 = 1.8025846e+34 J
Now it's the same, is there any other problem?

 

[ZawierJ]

If you think about the decimal point being slightly different. I will change it.

(0.64285714285 * 299792458^2) / (2 * 6.674x10^-11) = 4.3285225e+26 Kg

4.3285225e+26 / 5.972e+24 * 2.487e32 = 1.8025846e+34 J
Now it's the same, is there any other problem?

2,8730699e+54 Joule and 2,1119729e+58 Joule i found these results.

4.3285225e+26 / 5.972e+24 * 2.487e32 = 1.8025846e+34 J

Why did you do this? Also where did you find these numbers? (5.972e+24, 2.487e32)

 

[Second22]

2,8730699e+54 Joule and 2,1119729e+58 Joule i found these results.

Why did you do this? Also where did you find these numbers? (5.972e+24, 2.487e32)

Earth mass = 5.972e+24 kg
Earth GBE = 2.487e32 J

 

[Second22]

Dude, it's the same formula. just change the variable

Why did you do this?

To roughly estimate the Attack Potency level one can then compare its mass to either that of the earth or the sun, whichever is closer to its mass. If it's x times the mass of the object it is compared to we estimate that it's creation would equal about x times the energy needed to destroy said object, i.e. either x-times baseline planet level for earth or x-times baseline star level for the sun. ~ source

 

[Second22]

2,8730699e+54 Joule and 2,1119729e+58 Joule i found these results.

Can you show calculations? For black holes less than 1 m in size, I don't think it have 4-A energy levels.

 

[ZawierJ]

Can you show calculations? For black holes less than 1 m in size, I don't think it have 4-A energy levels.

Here. I know the calculation is wrong, it is my first black hole calculation.

 

[Second22]

Here. I know the calculation is wrong, it is my first black hole calculation.

The formula you use is for black holes with a radius exceeding 1477 m. You can read DT's response.

 

[ZawierJ]

The formula you use is for black holes with a radius exceeding 1477 m. You can read DT's response.

So, which formula should i use?

Earth mass = 5.972e+24 kg
Earth GBE = 2.487e32 J

What is The meaning of Earth GBE?

 

[Second22]

So, which formula should i use?

I have done the calculations and advised you above.

What is The meaning of Earth GBE?

Gravitational Binding Energy

Gravitational binding energy is the energy needed to completely disperse a celestial body. If GBE is broken, the particles of the body will not reform or be bound to each other's gravity, but instead drift off infinitely in the direction they were moved towards. There are precise calculations...

vsbattles.fandom.com

 

[ZawierJ]

4.3285225e+26 / 5.972e+24 * 2.487e32 = 1.8025846e+34 J
Now it's the same, is there any other problem?

I'm sorry but I still don't understand why you did this? Is it a formula?

 

[Second22]

I'm sorry but I still don't understand why you did this? Is it a formula?

I'm still not very good at give answering details. I only know in which cases numbers and variables are used.

 

[ZawierJ]

Ayrıntıları yanıtlama konusunda hâlâ pek iyi değilim. Sadece sayıların ve değişkenlerin hangi durumlarda kullanıldığını biliyorum.

Peki, emin olmak için tekrar sormak istiyorum What is the formula for calculating the joules of a black hole with a radius less than 1477 meters?

 

[Second22]

What is the formula for calculating the joules of a black hole with a radius less than 1477 meters?

((299792458^2/(2*6.674*10^-11))/(5.972*10^24))*(2.487*10^32) * radius in meters = energy in joules. It’s for black holes less than 1477m in radius

 

[ShionAH]

Peki, emin olmak için tekrar sormak istiyorum

He means “Okay but I am gonna ask again to make sure”

 

[KLOL506]

Does the black hole you calculated display properties of a real-life one? If not, it can't be assumed to be one and thus the calc would be bunk.