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AP Question

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So let’s say a character is Low Multi. And they have a infinite multiplier. What tier would that give. 2-A?
and now let’s say a char is 2-A, and also has an infinite multiplier. What tier would that be?
 
So let’s say a character is Low Multi. And they have a infinite multiplier. What tier would that give. 2-A?
it depends on how the context treats the infinite multiplier and also depends on the cosmology. But extremely likely it won't be 2-A at all.

As for the second one, just 2-A
 
2-C is only separated from 2-A by countable infinity so if the multiplier is infinite and multiplies their AP by Infinity they would be 2-A or 2-B through it.

2-A * Infinity is still 2-A though multiplication is not enough to get you to Low 1-C.
 
It depends on the context of the multiplier. Infinite multiplier means... He can no bust a universe more. Infinite more means bust another. Doesn't seem enough to reach 2-A.
 
We don’t allow multipliers for tier 2 characters as basis to reach a higher tier to begin with.
 
It depends on the context of the multiplier. Infinite multiplier means... He can no bust a universe more. Infinite more means bust another. Doesn't seem enough to reach 2-A.
The context is having force equivalent to an Infinite amount of low 2-C attacks.
 
1. If with infinite doubling he is able to release Energy as much as Low Multi at the same time, yes he can get 2A

2. Fixed 2A, if every Clone has the same Energy as Baseline 2A, so it will still be 2A
 
2-C x infinity = 2-C. It's weird logic but that's how it works on the wiki

I have seen multipliers used in 2-A before even very recently. It's just be infinitely above 2-A but range is a whole other can of worms.
 
So let’s say a character is Low Multi. And they have a infinite multiplier. What tier would that give. 2-A?
and now let’s say a char is 2-A, and also has an infinite multiplier. What tier would that be?
1. Depend on context and feat, but generally, it is still Low 2-C, because when destroy more than one space-time continuum, you not only need to destroy more than on but also overcome the distance between each space-time (which can be called 5th spatial dimension). It is similar to star level vs solar system level, the star contain 99% matters of all the solar system, but destroy it doesn't mean solar system; you need to destroy both the star/sun and breach the interplanetary distance, cover the entire solar system.

2. Infinite x 2-A = Infinite x Infinite = Infinite. Unless the verse specific about destroy more than one 2-A multiverse require more power/energy
 
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