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destroying 30 meters area with a punch

So.

Using this calculator, I found that a 30 meters area means a radius of 3.09 meters
Since you only gave the area, I have no idea exactly of how to find the volume, so I'll try doing the same thing as before.
I'll use 2 methods, depth being diameter * 0.18 (which is used for explosions) and depth being equal to radius (diameter * 0.5)

Using the first method, I get a volume of 22.2 cubic meters, which is 22.2 million cubic centimeters, assuming it's rock I'll use the values for fragmentation, violent fragmentation, pulverization and vaporization

Fragmentation (8j/cc): 0.04 tons of tnt (9-A)
Violent Fragmentation (69j/cc): 0.36 tons of tnt (8-C)
Pulverization (214j/cc): 1.13 tons of tnt (8-C+)
Vaporization (25700j/cc): 136 tons of tnt (8-A)

Using the second method, I get a volume of 61.79 cubic meters, which is 61.79 million cubic centimeters.

Fragmentation (8j/cc): 0.11 tons of tnt (9-A)
Violent Fragmentation (69j/cc): 1.01 tons of tnt (8-C)
Pulverization (214j/cc): 3.16 tons of tnt (High 8-C)
Vaporization (25700j/cc): 379 tons of tnt (8-A)
 
I just realized you worded it the same way as the 20km one, so if you mean 30 meters diameter (15 meters radius), the result would change

Using method 1 I get 2544 cubic meters which is 2.54 billion cubic centimeters.

Fragmentation (8j/cc): 4.86 tons of tnt (High 8-C)
Violent Fragmentation (69j/cc): 41.9 tons of tnt (8-B)
Pulverization (214j/cc): 130 tons of tnt (8-A)
Vaporization (25700j/cc): 15.6 kilotons of tnt (7-C)

Using method 1 I get 7068 cubic meters which is 7.06 billion cubic centimeters

Fragmentation (8j/cc): 13.5 tons of tnt (8-B)
Violent Fragmentation (69j/cc): 116 tons of tnt (8-A)
Pulverization (214j/cc): 361 tons of tnt (8-A)
Vaporization (25700j/cc): 43.4 kilotons of tnt (7-C)
 
So.

Using this calculator, I found that a 30 meters area means a radius of 3.09 meters
Since you only gave the area, I have no idea exactly of how to find the volume, so I'll try doing the same thing as before.
I'll use 2 methods, depth being diameter * 0.18 (which is used for explosions) and depth being equal to radius (diameter * 0.5)

Using the first method, I get a volume of 22.2 cubic meters, which is 22.2 million cubic centimeters, assuming it's rock I'll use the values for fragmentation, violent fragmentation, pulverization and vaporization

Fragmentation (8j/cc): 0.04 tons of tnt (9-A)
Violent Fragmentation (69j/cc): 0.36 tons of tnt (8-C)
Pulverization (214j/cc): 1.13 tons of tnt (8-C+)
Vaporization (25700j/cc): 136 tons of tnt (8-A)

Using the second method, I get a volume of 61.79 cubic meters, which is 61.79 million cubic centimeters.

Fragmentation (8j/cc): 0.11 tons of tnt (9-A)
Violent Fragmentation (69j/cc): 1.01 tons of tnt (8-C)
Pulverization (214j/cc): 3.16 tons of tnt (High 8-C)
Vaporization (25700j/cc): 379 tons of tnt (8-A)
I just realized you worded it the same way as the 20km one, so if you mean 30 meters diameter (15 meters radius), the result would change

Using method 1 I get 2544 cubic meters which is 2.54 billion cubic centimeters.

Fragmentation (8j/cc): 4.86 tons of tnt (High 8-C)
Violent Fragmentation (69j/cc): 41.9 tons of tnt (8-B)
Pulverization (214j/cc): 130 tons of tnt (8-A)
Vaporization (25700j/cc): 15.6 kilotons of tnt (7-C)

Using method 1 I get 7068 cubic meters which is 7.06 billion cubic centimeters

Fragmentation (8j/cc): 13.5 tons of tnt (8-B)
Violent Fragmentation (69j/cc): 116 tons of tnt (8-A)
Pulverization (214j/cc): 361 tons of tnt (8-A)
Vaporization (25700j/cc): 43.4 kilotons of tnt (7-C)
Thanks
 
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