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What energy is required to stop three planets the size of earth from colliding on each other
- Thread starter Danny1112
- Start date
- 6,014
- 2,123
Bleach i guess?
Dépend the speed, if it's isn't precised, it's Baseline
Dépend the speed, if it's isn't precised, it's Baseline
- 6,014
- 2,123
Bleach have the same feat so I thought about that
- 6,014
- 2,123
This is pretty weird I don't really know but if these 3 planets are completely destroyed, it's above Baseline if not IDK
- 533
- 43
- Thread starter
- #7
Ah,maybe it's your first time seeing this question,sorry if it seems weird tho,to put my points clearly, when three planets comes too close to each other they cause a devastating environmental destruction on their surfaces before they hit due to their gravity pulling on each other at least that's what I read from a site,so I was asking what energy would be required from stopping them at that point with sheer power.The Causality said:
- 3,464
- 891
Depends on how fast they were moving. If you know that, then you can just throw in the KE formula and multiply by 3
- 533
- 43
- Thread starter
- #9
The thing is,this is just a random question,so there is no way I can get a speed,but is there a case for assumption or average speed for the movement of a planet??let say the planet wasn't pushed by anybody,it just roamed freely, note" the three planets are moving at each other not just one planet moving at another.and I need someone to calc it for me,am not good at calcs that much lol,especially if it deals with ap.Crimson Azoth said:
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The energy would be equivalent to greater than the KE of the three planets combined.
KE = 1/2m x v^2
m = mass in kg
v = velocity in m/s
If we assume exact Earth conditions as in RIGHT NOW (not in the gravitational pull of some other planet like object at close range, as that would severely alter results), we have a velocity equivalent to 30000 m/s (roughly) and a mass equivalent to 5.972e24 kg.
KE = (0.5 x 5.972e24) x 30000^2 = 2.688e33 Joules
Multiply by three to get a net value of 8.063e33 Joules, or 1.93 Yottatons of TNT, Planet level+.
Hope this helped.
KE = 1/2m x v^2
m = mass in kg
v = velocity in m/s
If we assume exact Earth conditions as in RIGHT NOW (not in the gravitational pull of some other planet like object at close range, as that would severely alter results), we have a velocity equivalent to 30000 m/s (roughly) and a mass equivalent to 5.972e24 kg.
KE = (0.5 x 5.972e24) x 30000^2 = 2.688e33 Joules
Multiply by three to get a net value of 8.063e33 Joules, or 1.93 Yottatons of TNT, Planet level+.
Hope this helped.
- 3,464
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1287 zettatons. Or 1.287 yottatons
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