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No, aleph 2 number of whatever element is that is low 1A by defaultNo, we don't.
An Aleph-Null amount of sand is High 3-A, an Aleph-1 is Low 2-C, and an Aleph-3 amount is Low 1-C, so on and so forth up to High 1-B.
An Aleph-Null of Universes is 2-A, and Aleph-1 of Universes is Low 1-C, and so on and so forth up to High 1-B.
However, the same does not necessarily apply when approaching sets of higher cardinalities than this (Such as P(P(ℵ0)), the power set of the power set of aleph-0), as they would be strictly bigger than all of the spaces mentioned above, by all rigorous notions of size, regardless of what their elements are. From this point and onwards, all such sets are Low 1-A at minimum.
Whoever told you that is wrong then.No, aleph 2 number of whatever element is that is low 1A by default
It's from the FAQ...Whoever told you that is wrong then.
It's from the FAQ...
It's literally stated that 1-A can be extended using Alephs, just like 1-C can be extended to 1-B.This can be extrapolated to larger cardinal numbers as well, such as aleph-3, aleph-4, and so on, and works in much the same way as 1-C and 1-B in that regard.
Low 1-A is effecting an uncountably infinite number of dimensions, meanwhile Low 1-C.Characters or objects that can affect structures with a number of dimensions greater than the set of natural numbers, meaning in simple terms that the number of dimensions is aleph-1 (An uncountably infinite number, assumed to be the cardinality of the real numbers themselves)
Characters or objects that can universally affect, create and/or destroy spaces whose size corresponds to one to two higher levels of infinity greater than a standard universal model (Low 2-C structures, in plain English.)
Is affecting a higher level of infinity, and they specifically use R^5 as an example, with real numbers being the cardinality of uncountable infinity, also known as Aleph -1.In terms of "dimensional" scale, this can be equated to 5 and 6-dimensional real coordinate spaces (R ^ 5 to R ^ 6)
So no, whoever told him that is wrong, and if it's on the FAQ then it's a contradiction.aleph-1 (An uncountably infinite number, assumed to be the cardinality of the real numbers themselves),
"just like 1-C can be extended to 1-B" is to reference that each aleph would be a layer higher into 1-A (aleph-3 dimensions would be one layer above baseline, aleph-4 would be two layers above baseline, and so on), but thats not the case with the tiers lower. Since, for example, an aleph-1 amount of breads would be Low 2-C while an aleph-1 amount of dimensions is Low 1-A. It depends on what you apply Aleph-1 quantity into (all the tiers from 11-B to Low 1-A are applications of Aleph-1, such as R^1, R^2, R^3, R^4, etc). But when it comes to aleph-2 and higher, it isn't, since even the lowest application of Aleph-2, such as R^R^1, is still R^R and thus already bigger than anything else Aleph-1 could offer.It's literally stated that 1-A can be extended using Alephs, just like 1-C can be extended to 1-B.
It indeed is on the FAQSo no, whoever told him that is wrong, and if it's on the FAQ then it's a contradiction.
Oh, it's R^Number, not R^R, I'm stupid, never mind.
Cardinality is the size of the set bruhAleph 1 isn’t a set, it’s a cardinality. So the power set of it doesn’t make sense. Aleph 2 is the smallest cardinal larger than aleph 1. Aleph 2, according to GCH, is the cardinality of the power set of a set with cardinality aleph 1
Cardinal is size of set (whatever set is that). That universal bruh... not in hierarchy of infinitiesWould cardinals still be above alephs in general?
Reading comprehension devil strike again.Cardinality is the size of the set bruh
If pressed for a yes or no answer I would say the aleph_0 is a limit cardinal, yes: the set of all smaller cardinals doesn't have a largest element.Would cardinals still be above alephs in general?
Where you get, aleph 1 isnt a set?Reading comprehension devil strike again.