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Shake and Destroy the Burj Khalifa

I have calculated the energy required to destroy Burj Khalifa and it's estimated at 3.9 x 10¹² , which is 8-A (multi city block )
 
I have calculated the energy required to destroy Burj Khalifa and it's estimated at 3.9 x 10¹² , which is 8-A (multi city block )
I don't think so. The reference for common feats has destruction of a normal skyscraper around 8-A (though it's still 9x lesser than your result).

I tried to give it a shot and got tier 7 results lol

According to Wikipedia, Burj Khalifa's construction mainly used 330,000 m3 (431,600 cu yd) of concrete and 55,000 tonnes (61,000 short tons; 54,000 long tons) of steel rebar, and construction took 22 million man-hours.

According to this, Burj Khalifa used stainless steel and steel-reinforced concrete.

I will use destruction values of reinforced concrete and stainless steel from here.

First of all,
  • Volume of reinforced concrete = 330000 m3 = 330000000000 cc
  • Volume of steel (calculating via the density of steel as 7500 kg/m3) for 55000 tonnes or 55000000 kg = 55000000/7500 = 7333.33333333 m3 = 7333333333.33 cc

Fragmentation-end (basic destruction):
  • For reinforced concrete = 330000000000*10 = 3300000000000 J
  • For stainless steel = 7333333333.33*358 = 2.6253333e+12 J
  • Total Energy/Attack Potency = 2.6253333e+12+3300000000000 = 5.9253333e+12 J or 1416.188647227533 tons of tnt or 1.416188647227533 kilotons of tnt (Small Town level)

Violent Fragmentation-end (small rubble):
  • For reinforced concrete = 330000000000*61.2 = 2.0196e+13 J
  • For stainless steel = 7333333333.33*597 = 4.378e+12 J
  • Total Energy/Attack Potency = 2.0196e+13+4.378e+12 = 2.4574e+13 J or 5873.3269598470361 tons of tnt or 5.8733269598470361 kilotons of tnt (Town level)

Pulverization-end (dust or very small particles):
  • For reinforced concrete = 330000000000*610 = 2.013e+14 J
  • For stainless steel = 7333333333.33*1631 = 1.1960667e+13 J
  • Total Energy/Attack Potency = 2.013e+14+1.1960667e+13 = 2.1326067e+14 J or 50970.5234225621389 tons of tnt or 50970.5234225621389 kilotons of tnt (Town level)
 
I don't think so. The reference for common feats has destruction of a normal skyscraper around 8-A (though it's still 9x lesser than your result).

I tried to give it a shot and got tier 7 results lol

According to Wikipedia, Burj Khalifa's construction mainly used 330,000 m3 (431,600 cu yd) of concrete and 55,000 tonnes (61,000 short tons; 54,000 long tons) of steel rebar, and construction took 22 million man-hours.

According to this, Burj Khalifa used stainless steel and steel-reinforced concrete.

I will use destruction values of reinforced concrete and stainless steel from here.

First of all,
  • Volume of reinforced concrete = 330000 m3 = 330000000000 cc
  • Volume of steel (calculating via the density of steel as 7500 kg/m3) for 55000 tonnes or 55000000 kg = 55000000/7500 = 7333.33333333 m3 = 7333333333.33 cc

Fragmentation-end (basic destruction):
  • For reinforced concrete = 330000000000*10 = 3300000000000 J
  • For stainless steel = 7333333333.33*358 = 2.6253333e+12 J
  • Total Energy/Attack Potency = 2.6253333e+12+3300000000000 = 5.9253333e+12 J or 1416.188647227533 tons of tnt or 1.416188647227533 kilotons of tnt (Small Town level)

Violent Fragmentation-end (small rubble):
  • For reinforced concrete = 330000000000*61.2 = 2.0196e+13 J
  • For stainless steel = 7333333333.33*597 = 4.378e+12 J
  • Total Energy/Attack Potency = 2.0196e+13+4.378e+12 = 2.4574e+13 J or 5873.3269598470361 tons of tnt or 5.8733269598470361 kilotons of tnt (Town level)

Pulverization-end (dust or very small particles):
  • For reinforced concrete = 330000000000*610 = 2.013e+14 J
  • For stainless steel = 7333333333.33*1631 = 1.1960667e+13 J
  • Total Energy/Attack Potency = 2.013e+14+1.1960667e+13 = 2.1326067e+14 J or 50970.5234225621389 tons of tnt or 50970.5234225621389 kilotons of tnt (Town level)
And to shake it?
 
And to shake it?
By "shake it", do you mean shaking it by lifting it in the air? Or by shaking while it is still on the ground and along with the ground? I believe the first one can be calculated once you send me a feat where this happens (because it also depends upon how violently and badly one shakes it) and the latter is an earthquake feat, might want to check this out for it and try to match the magnitude.

Just telling, you might need to get the calculation of destroying it evaluated as well.
 
By "shake it", do you mean shaking it by lifting it in the air? Or by shaking while it is still on the ground and along with the ground? I believe the first one can be calculated once you send me a feat where this happens (because it also depends upon how violently and badly one shakes it) and the latter is an earthquake feat, might want to check this out for it and try to match the magnitude.

Just telling, you might need to get the calculation of destroying it evaluated as well.
I don't have a feat where the Burj Khalifa is destroyed or shaken, but a feat where a character shakes a similar structure in his anger.
The structure in question is possibly as tall as or larger than the Burj Khalifa and it is wider, so I wanted to have a point of comparison.
 
I don't have a feat where the Burj Khalifa is destroyed or shaken, but a feat where a character shakes a similar structure in his anger.
The structure in question is possibly as tall as or larger than the Burj Khalifa and it is wider, so I wanted to have a point of comparison.
Use this formula to calculate the velocity:

Velocity = (Displacement from the center of mass on every swing)(Directions in which the character shakes the building)(3.14)*(No. of times the character shakes the building in a second)

For no. of times the character shakes the building in a second, 30 Hz might be a good option if it is just vibrations.

Then, when you find the velocity, put it in the kinetic energy formula as:

Attack Potency via Kinetic Energy = 0.5*(Mass of the building)*(Velocity found before)^2

I used reference from this accepted calculation by the way.
 
Can we calculate this from the durability of the structure?If the skyscraper can tank a nuke, what result would that give to the feat?
No, that would just mean that the nuke had less PSI pressure in the explosion, and let's say you somehow are able to prove the otherwise, then also I think that it would just count as calc-stacking, as it is pretty much applying result of another calc into another calc.
 
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