Question regarding dimensionality

[Swordsaint456]

I was looking through the recent(ish) ben 10 hyperversal thread and they said because the axis are infinite it would be enough for QS. but how so? The cardinality of an axis (within the context of our 3 dimensions) is

which basically means the cardinality of an axis is uncountable, not infinite. which means they would've had to prove the axis are uncountable and not just infinite. or am I misinterpreting something???
(accidentally posted this in general discussion

 

[Swordsaint456]

SUPA BUMP!

 

[BestMGQScalerEver]

If a 3rd spatial axis is infinite and so is the 4th one then the 4th one would basically have an uncountable infinite difference over it I guess.

 

[Reiner04]

You just gotta prove dimensions are fully sized, they would have auto uncountable difference. Well technically dimensions are treated fully sized unless contradicted or depicted otherwise but meh.

 

[Swordsaint456]

If a 3rd spatial axis is infinite and so is the 4th one then the 4th one would basically have an uncountable infinite difference over it I guess.

how so?

 

[Reiner04]

how so?

3D would have 0 width along 4d. As long as 4D is significantly large, that's all needed. Refers to our FAQ section of "Is bigger than 2-A Low 1-C"

 

[Swordsaint456]

i see