Moving a rotatable object

[Ian2296]

How do I search the force that's reduced from the rotation mechanism? I already find the weight of the total room which is around 2652 kg, but that's clearly not the total weight he pushed since he's helped by the rotation force, so how do I find the exact force?

 

[Ian2296]

Bump

 

[FinePoint]

First find torque.
τ = m*(r^2)*α
m: Mass (kg)
r: Radius (m)
α: Angular Acceleration (Radians/s^2)

Convert to force.
F = τ/(r*sin(a))
τ: Torque (Nm)
r: Radius (m)
a: Angle (Radians)

Since he seems to push it perpendicular, the second step will simplify to F = τ/r
If you plug with previous equation, you'll simplify to F = mrα for your case.

 

[Ian2296]

Do I get the radius from the width of the room? (Distance from the front of the room to the back of the room)

 

[FinePoint]

Do I get the radius from the width of the room? (Distance from the front of the room to the back of the room)

From the center to where he pushed it.

 

[Ian2296]

From the center to where he pushed it.

Yeah I mean from the center (but I'll lowball it using the width of the room)

Anyway thank you very much for the formula.

 

[Ian2296]

α: Angular Acceleration (Radians/s^2)

How do you find the Angular Acceleration? I already found the radians which is 0,21433 rad. Do I just plug the radians to /s² and it will be 0,21433rad/s²?

 

[GilverTheProtoAngelo]

That's prolly angular distance...
You need to derive acceleration out of it with help of time.
Angle moved during torque application= alpha(angular acceleration) ×t²
t=time duration of push
Since the motion starts from rest.