- 9,956
- 1,999
- Thread starter
- #81
Ok, you may unlock the page and I'll add the values.
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Guidelines for Surface Explosions
- Thread starter Antoniofer
- Start date
- 164,978
- 71,714
I have unlocked it. Tell me here when you are done.
vsbattles.fandom.com
Explosion Yield Calculations
First, you have to find the exact page, or scene where an explosion is shown as a feat. Depending on the environment where the explosion occurred, you may have to scale the size of a smaller object that is shown in the map. Let's do an example... An explosion of unknown size occurs in this...
vsbattles.fandom.com
- 9,956
- 1,999
- Thread starter
- #83
Ok, already added the values; if someone want to change the brief explaination I added, feel free to do it if you consider it appropiated.
- 9,956
- 1,999
- Thread starter
- #87
The guidelines for what overpressure value use depending of the destruction caused by the detonation. DontTalkDT never argued more about it, but I do not recall him directly opposing it, and few other users agreed with the concept.
- 32,737
- 37,876
Not sure. Most of the stuff left has been done.
- 164,978
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Can you write a more indepth, but preferably easy to understand, explanation please?
- 32,737
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Basically the various overpressure values we use for explosions based on what material the destroyed object was made out of.
- 164,978
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UeTa
She/Her- 426
- 569
Hello there, I know this is a very old thread, but I'm asking here anyways since I don't find a answer anywhere else.
In This equation:
Also while I'm at it. Do any one of you know how to calculate explosion in extremely low density environment? Like a vacuum, space or Earth low-orbit?
Thank you for your response in advance.
In This equation:
((x/0.28) ^3) /1000 (The Mid-air explosion) What's "0.28" stand for? Is this the pressure in psi?Also while I'm at it. Do any one of you know how to calculate explosion in extremely low density environment? Like a vacuum, space or Earth low-orbit?
Thank you for your response in advance.
- 164,978
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@DontTalkDT
Your help would still be appreciated here:
Or is there any other calc group member who has good suggestions regarding what we should do here?
Your help would still be appreciated here:
Or is there any other calc group member who has good suggestions regarding what we should do here?
- 9,956
- 1,999
- Thread starter
- #94
I believe 0.28 is just a constant obtained after simplefying the equation taking 20 psi as reference; the original equation is unknown to me.
UeTa
She/Her- 426
- 569
I'm not a calc' group member, but for surface level explosion I know that 3,000 psi is enough to destroy most renforced missile bunkers and 30,000 to 300,000 psi is the common value to destroy steel. Depending of its general quality.
UeTa
She/Her- 426
- 569
So 0.28 = 20 psi.
Meaning 1 psi = 0.014 of this "thing"?
- 9,956
- 1,999
- Thread starter
- #98
The relationship is most likely not linear; the surface-level explosion calc is not linear if that works as reference for you.
UeTa
She/Her- 426
- 569
Ah, too bad. I thought it would be possible to keep it linear with values lower than 20 psi (5 psi or lower) and values going into far higher than 0.28 would just switch "/" to "*" lol.
I imagine we have to find the unsimplified equation to made it work. Otherwise we are stuck with 20 psi airburst explosion.
- 32,737
- 37,876
The formula is mostly derived from the Nuke Calculator, at least, that's what DontTalkDT told me, said that there was a technique to uncovering the formula used by inspect searching or some shit, but I suck at coding so I wouldn't be able to give a straight answer.
UeTa
She/Her- 426
- 569
Ah ok, gonna try to search for it then. Thanks!
UeTa
She/Her- 426
- 569
I found it.
And the psi scaling for the simplified equation works like this :
And the psi scaling for the simplified equation works like this :
- 1 psi = 2.2
- 3 psi = 1.0
- 5 psi = 0.71
- 10 psi = 0.45
- 20 psi = 0.28
UeTa
She/Her- 426
- 569
Scottycj256
He/Him- 1,758
- 901
lets ******* go
- 11,173
- 17,296
We should probably add this to the explosions calculation page. There are some feats that involve shockwaves (which fall under air bursts) that cause minor damage that wouldn't fall under 20 psi.
Honestly, we should also establish guidelines for which psi to use for a given feat. This part should be pretty easy, as the website that has these psi values also has descriptions of what would fall under each psi value.
For reference, here is what each psi value describes:
1 psi: Window glass shatters. Light injuries from fragments occur.
3 psi: Residential structures collapse. Serious injuries are common, fatalities may occur.
5 psi: Most buildings collapse. Injuries are universal, fatalities are widespread.
10 psi: Reinforced concrete buildings are severely damaged or demolished. Most people are killed.
20 psi: Heavily built concrete buildings are severely damaged or demolished. Fatalities approach 100%.
- 164,978
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Anyway...
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I do not mind, but it depends on what other calc group members (and @DontTalkDT ) think.
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