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Mahoraga victim 


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Base Deku victim
Uraraka victimNObara > verse
Nobara mogs broUraraka victim
O, top right
X, bottom rightO, top right
O, top leftX, bottom right
X, top middleO, top left
O, bottom middleX, top middle
X, middle leftO, bottom middle
idk how I won but thanksDamn, you win. GG
But O, bottom left
My brother in christ you are speaking in moon runesZ3C
∞
Σ¹/nz = 0
n=z
Va E N, z ≠ −2a
Re(z) = you getting laid which the odds of that are 1 and 1.5 but just pretend 1.5 is even an odd number which your dumbass didn't even know it wasn't. But now substantiate how
Y →൮ = lim n
n→∞ (Σ 1/k — in ñ)
k=1
Objectively and subjectively in truth proves you were raised by a father but rather now in opposite truths you were raised by a deformed turtle but now the turtle wants you to solve your final exam question via
3n + ∛n2 + 8⇒×3n ≡ ∞⁹⁹⁹≈ℰ″ε°>√n2 + 8 = x ≈ ∞ε⇔ ≡ 99837⁹⁹_⁷⅞²⅓7837⁸
∈⇔67 + 92793⁹ γ≈55¬½ + ‰ ⊥≡ the 100%‰
≝ ℳ ⊗ ℝ =Ξ8936⁹°⁹
And how you solving this higher plane of existence problem helps you getting a girlfriend + don't forget Fermat’s Last Theorem: The problem is to finding solutions to the equation xn+yn=zn��+��=�� where n� is some positive number. The case for n=1,2�=1,2 has trivially many solutions but Fermat conjectured that there exits no solution for n>2�>2,for instance one cannot find a solution to the equation x3+y3=z3�3+�3=�3 no matter how far you look for the triple (x,y,z).
Which now goes into ζ(s)=∑n=1∞1ns -> s=1/2 as it’s real part. The Conjecture then is that all non-trivial zeros lie on the critical strip. And now into
1782¹² + 1841¹² + 1922¹² P ≈ N X⁵
4Rur –– 1¹/2⁸ R gur + A gur = 8‡±Rg/tC⁴-Tur